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nadya68 [22]
2 years ago
6

Anyone trying to play fortnite ? im bored lol

Computers and Technology
2 answers:
kkurt [141]2 years ago
7 0

Answer:

what arena division r u in

and nr

Explanation:

Greeley [361]2 years ago
7 0

Answer:

no

Explanation:

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kompoz [17]
The correct answer for this question is this one: "a. wireless local area network (WLAN)."

<span>The technology that is predominately used for contactless payment systems is called the </span><u>wireless local area network (WLAN)</u><u />. It is even used now a days.
Hope this helps answer your question and have a nice day ahead.
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2 years ago
It keeps saying “something is going wrong oops!” when i click on my brainly notifications what do I do
AveGali [126]

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If a user wants to add an expansion card to increase the memory of a computer, where should the user insert the card?
uysha [10]

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6 0
3 years ago
Read 2 more answers
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
A security system uses sensors at every door and window which will set off an alarm if any one of them is opened. There is also
AnnyKZ [126]
You have a raspberry pi connected to all the sensors and a code running to  trigger if the sensors are triggered. Each sensor and keypad would run to a different input on the pi. They should al be able to be powered with a single cell lipo. Is that what you are asking?
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