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timama [110]
3 years ago
6

Six tools are in a bag – a hammer, wrench, drill, pliers, screwdriver, and measuring tape. You are trying to find the probabilit

y that you will pull out a different tool each time, if you replace the tool after each pull. Which simulation design would most accurately predict the result of choosing a tool three times?
Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
4 0

Answer:

A dice with six sides

Step-by-step explanation:

In the problem , we are given that a bag is full of six tools, hence there are six possible results. Hence we have to guess a same event in which we have six different possible outcomes.

It is also given that , after every draw , the tool is again replaced in the bag. Means we have the equal possibility of drawing the same tool in the next draw also.

Hence we can go with the rolling a dice. A dice has six faces , with different numbers and each throw gives you a six possible result. Also we have the possibility of getting same number in the next throw also.

Vesna [10]3 years ago
3 0
You could roll a 6-sided die 3 times to simulate this.  This is a good simulation because it has one side for each possible tool, and each roll is independent, just as selecting the tool with replacement would be.
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Can someone please help me
Shtirlitz [24]

Answer:

The answer is A

5 0
2 years ago
1 - 10x = 81 <br> Value of X?
igomit [66]

x = -8

Step-by-step explanation:

Step 1: Subtract 1 from both sides

1 - 10x - 1 = 81 - 1 \\  - 10x = 80

Divide both sides of the equation by -10

\frac{ - 10x}{ - 10}  =  \frac{80}{ - 10}  \\  \\ x =  - 8

4 0
3 years ago
Read 2 more answers
Evaluate the expression t-6/4 for t =38
Finger [1]

Answer:

Exact Form:

73  over 2

Decimal Form:

36.5

Mixed Number Form:

36   1 over 2

Step-by-step explanation:

Substitute the value of the variable into the equation and simplify.

8 0
3 years ago
PLEASE someone help its due tonight im almost done
marusya05 [52]
<h3>Answers:</h3>
  • 48 seconds
  • 3624 feet

========================================================

Explanation:

x = number of seconds that elapse

y = altitude (aka height) of the plane

The equation for plane A is

y = 20.25x+2652

because it starts off at 2652 ft in the air, and then adds on 20.25 feet per second which is what the 20.25x describes

The equation for plane B is

y = 75.5x

The y intercept is zero because plane B starts on the ground, aka height 0.

------------------

The system of equations is

\begin{cases}y = 20.25x+2652\\y = 75.5x\end{cases}

If we want to know when they'll reach the same height (y), then we can set the two right hand sides equal to each other and solve for x.

75.5x = 20.25x+2652

75.5x-20.25x = 2652

55.25x = 2652

x = (2652)/(55.25)

x = 48

The two planes reach the same altitude at exactly <u>48 seconds</u>

That altitude is <u>3624 feet</u> because

  • y = 20.25*x + 2652 = 20.25*48+2652 = 3624
  • y = 75.5*x = 75.5*48 = 3624

Notice I plugged x = 48 into each equation and I got the same y value of y = 3624. This helps confirm the answers.

7 0
2 years ago
Find the GCF for the list.<br> - 6x^2, 21x^3
wolverine [178]

Answer:

3x^2

Step-by-step explanation:

3x^2 can be factored out of each

-6x^2 = 3x^2(-2)

21x^3 = 3x^2(7x)

6 0
2 years ago
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