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timama [110]
3 years ago
6

Six tools are in a bag – a hammer, wrench, drill, pliers, screwdriver, and measuring tape. You are trying to find the probabilit

y that you will pull out a different tool each time, if you replace the tool after each pull. Which simulation design would most accurately predict the result of choosing a tool three times?
Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
4 0

Answer:

A dice with six sides

Step-by-step explanation:

In the problem , we are given that a bag is full of six tools, hence there are six possible results. Hence we have to guess a same event in which we have six different possible outcomes.

It is also given that , after every draw , the tool is again replaced in the bag. Means we have the equal possibility of drawing the same tool in the next draw also.

Hence we can go with the rolling a dice. A dice has six faces , with different numbers and each throw gives you a six possible result. Also we have the possibility of getting same number in the next throw also.

Vesna [10]3 years ago
3 0
You could roll a 6-sided die 3 times to simulate this.  This is a good simulation because it has one side for each possible tool, and each roll is independent, just as selecting the tool with replacement would be.
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Find the slope of the line that passes through K(-4,4), L(5,4)
Sergeu [11.5K]

Answer:

The slope is 0, or it is a zero slope.

Step-by-step explanation:

The y coordinate is 4 throughout, and if it were the x coordinate that stayed the same for both points, it would be a undefined slope.

4 0
3 years ago
The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in in
Grace [21]

Answer:

A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Step-by-step explanation:

We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;

68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2,  76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.

Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;

                             P.Q.  =  \frac{(n-1) \times s^{2} }{\sigma^{2} }  ~ \chi^{2} __n_-_1

where, s = sample standard deviation = \sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} } = 5.063

            \sigma = population standard deviation

            n = sample of observations = 22

Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.

<u>So, 90% confidence interval for the population standard deviation, </u>\sigma<u> is ;</u>

P(11.59 < \chi^{2}__2_1 < 32.67) = 0.90  {As the critical value of chi at 21 degrees  

                                                  of freedom are 11.59 & 32.67}  

P(11.59 < \frac{(n-1) \times s^{2} }{\sigma^{2} } < 32.67) = 0.90

P( \frac{ 11.59}{(n-1) \times s^{2}} < \frac{1}{\sigma^{2} } < \frac{ 32.67}{(n-1) \times s^{2}} ) = 0.90

P( \frac{(n-1) \times s^{2} }{32.67 } < \sigma^{2} < \frac{(n-1) \times s^{2} }{11.59 } ) = 0.90

<u>90% confidence interval for</u> \sigma^{2} = [ \frac{(n-1) \times s^{2} }{32.67 } , \frac{(n-1) \times s^{2} }{11.59 } ]

                                     = [ \frac{21 \times 5.063^{2}  }{32.67 } , \frac{21 \times 5.063^{2}  }{11.59 } ]

                                     = [16.48 , 46.45]

<u>90% confidence interval for</u> \sigma = [\sqrt{16.48} , \sqrt{46.45} ]

                                                 = [4.06 , 6.82]

Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

5 0
3 years ago
The employees at a bank ordered 2 turkey sandwiches and 4 salads from a local deli. The total cost for the order was $23. If a s
Alex

Answer:

Cost of turkey sandwich is $4.50 and cost of salad is $3.50

Step-by-step explanation:

Let cost of 1 turkey sandwich be $t and cost of 1 salad be $s.

2t + 4s = 23 --(1)

s + 1 = t

s = t - 1 --(2)

Sub (2) into (1):

2t + 4(t - 1) = 23

6t - 4 = 23

6t = 27

t = 4.5

sub t = 4.5 into (2):

s = 4.5 - 1

s = 3.5

therefore, cost of turkey sandwich is $4.50 and cost of salad is $3.50

8 0
3 years ago
Do not change the order of the numbers. You may put two numbers together to form a two-degit number.
LenKa [72]
1 + 2 + 3 + 4 + 5 + 67 + 8 = 90

I think this is what you mean right?
7 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
geniusboy [140]

Answer:

a ) n = 1667

b) n= 5192

c) n=1500

Step-by-step explanation:

c= 95%

Expected value = E.v= 300 , 170 , 100

R = 35000-10000=25000

σ = R / 4 = 25000 / 4 = 6250

For sample size

b = ( zα/2  / 2σ  / E )^2

where 1-α = 0.95 and

zα/2 = 1.96

then putting values one by one of E we get

E.v = 300

  n= 1667

E.v = 170

n=5192

E.v =100

n= 1500

so for

a ) n = 1667

b) n= 5192

c) n=1500

8 0
3 years ago
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