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timama [110]
3 years ago
6

Six tools are in a bag – a hammer, wrench, drill, pliers, screwdriver, and measuring tape. You are trying to find the probabilit

y that you will pull out a different tool each time, if you replace the tool after each pull. Which simulation design would most accurately predict the result of choosing a tool three times?
Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
4 0

Answer:

A dice with six sides

Step-by-step explanation:

In the problem , we are given that a bag is full of six tools, hence there are six possible results. Hence we have to guess a same event in which we have six different possible outcomes.

It is also given that , after every draw , the tool is again replaced in the bag. Means we have the equal possibility of drawing the same tool in the next draw also.

Hence we can go with the rolling a dice. A dice has six faces , with different numbers and each throw gives you a six possible result. Also we have the possibility of getting same number in the next throw also.

Vesna [10]3 years ago
3 0
You could roll a 6-sided die 3 times to simulate this.  This is a good simulation because it has one side for each possible tool, and each roll is independent, just as selecting the tool with replacement would be.
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Screenshot of the question attatched. please help me
Law Incorporation [45]
<h2>Rules of Exponents</h2>

There are many rules that apply to operations involving exponents. In this question, we'll need the following:

<h3>The division rule</h3>
  • ⇒ \dfrac{a^n}{a^m}=a^{n-m}

<h2>Solving the Question</h2>

We're given:

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\dfrac{z^{21}}{z^7}=z^k

⇒ Use the division rule:

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Therefore, the value of <em>k</em> is 14.

<h2>Answer</h2>

<em>k</em> = 14

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Step-by-step explanation:

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