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Mila [183]
4 years ago
6

Help please, i need a maths wizz!! :( (See pinned pics for questionS)

Mathematics
1 answer:
lana66690 [7]4 years ago
8 0

Answer:

200 people attended screen 1

150 to screen 2 and 150 to screen 3

for question 2:it's 265.1

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A cake is removed from an oven. The temperature, in degrees Fahrenheit, of the cake after t minutes can be modeled by the equati
Montano1993 [528]

Answer:

210°F

110 minutes

Step-by-step explanation:

Given that :

Temperature of cake t minutes after being removed from oven :

f(x)=70+140e^-0.024t

Temperature T the timee it is removed ;

At this point, the time t = 0

f(t)=70+140e^-0.024t

f(x)=70+140e^-0.024(0)

= 70 + 140(1)

= 210°F

how long will it take for the cake to reach a temperature of 80oF

80 = 70+140e^-0.024t

80 - 70 = 140*e^-0.024t

10/140 = e^-0.024t

0.0714285 = e^-0.024t

In(0.0714285) = - 0.024t

−2.639057 = - 0.024t

t = 2.639057 / 0.024

t = 109.9607

t = 110 minutes

5 0
3 years ago
Two and three hundredths is how much less than three and two tenths? Write the answer in words
baherus [9]
Two and three hundredths is one and seventeen hundredths less than three and two tenths.
4 0
3 years ago
PERMUTATION:
horsena [70]

Answer:

28

Step-by-step explanation:

It can be a one digit no.

_

2C1 = 2 (only two even options available)

It can be a 2 digit no.

_ _

The last digit has to be even for the no. to be even.

2C1 × 4C1 = 8 (2C1 for the last digit, 4C1 for the first)

It can be a 3 digit no.

_ _ _

First digit has to be less than 5 to be less than 500, and the last digit has to be even.

1) 2/4 _ 4

2C1 × 3C1 = 6 (2C1 to choose between 2 and 4, 3C1 for the second digit)

2) 1/3 _ 2/4

2C1 × 3C1 × 2C1 = 12 (2C1 to choose between 1 and 3, 3C1 for the second digit, 2C1 to choose between 2 and 4)

Total = 2 + 8 + (6 + 12)

= 28

5 0
4 years ago
craig scored 12 points in a game marla scored twice as many points as craig but 5 fewer points than nelson scored write an expre
12345 [234]
12(2)+5

Dang, you're an elementary school er? Good grief i'm and 8th grade math one student!
8 0
3 years ago
Coffee beans worth $ 10.50 $10.50 per pound are to be mixed with coffee beans worth $ 13.00 $13.00 per pound to make 50 50 pound
MAVERICK [17]

Answer: 30 pounds of coffee beans worth $10.50 per pound was used.

20 pounds of coffee beans worth $13.00 per pound was used.

Step-by-step explanation:

Let x represent the number of coffee beans worth $10.50 per pound that should be mixed.

Let y represent the number of coffee beans worth $13.00 per pound that should be mixed.

50 pounds of beans worth $11.50 per pound is to be made. The total cost of the mixture would be

50 × 11.5 = 575

This means that

10.5x + 13y = 575 - - - - - - - 1

The total number of pounds of each type of coffee used is 50. This means that

x + y = 50

Substituting x = 50 - y into equation 1, it becomes.

10.5(50 - y) + 13y = 575

525 - 10.5y + 13y = 575

- 10.5y + 13y = 575 - 525

2.5y = 50

y = 50/2.5 = 20

x = 50 - 20= 30

6 0
4 years ago
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