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3 years ago

Which of the following, is not a solution for the inequalities is represented by the graph shown?

Mathematics

1 answer:

stealth61 [152]3 years ago

3 0

Answer:

(0,1)

Step-by-step explanation:

This is because (0,1) is right on the line, while the other choices are inside of the blue shaded area.

If this answer is correct, please make me Brainliest!

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Responses which are acquired after birth are called _____ responses.

hichkok12 [17]

Answer:

Learned

Step-by-step explanation:

I luv u!

7 0

2 years ago

Factorise fully 16c^4p^2+20cp^3

DiKsa [7]

Given the expression below:

$\large \boxed{16 {c}^{4} {p}^{2} + 20c {p}^{3} }$

We can factor out c-term, p² and 4 (from 16 and 20)

$\large{4c {p}^{2} (4 {c}^{3} + 5p)}$

Answer

4cp²(4c³+5p)

4 0

2 years ago

Read 2 more answers

Evaluate the Riemann sum for f(x) = 3 - 1/2 times x between 2 and 14 where the endpoints are included with six subintervals taki

Digiron [165]

Answer:

-6

Step-by-step explanation:

Given that :

we are to evaluate the Riemann sum for $f(x) = 3 - \dfrac{1}{2}x$ from 2 ≤ x ≤ 14

where the endpoints are included with six subintervals, taking the sample points to be the left endpoints.

The Riemann sum can be computed as follows:

$L_6 = \int ^{14}_{2}3- \dfrac{1}{2}x \dx = \lim_{n \to \infty} \sum \limits ^6 _{i=1} \ f (x_i -1) \Delta x$

where:

$\Delta x = \dfrac{b-a}{a}$

a = 2

b =14

n = 6

∴

$\Delta x = \dfrac{14-2}{6}$

$\Delta x = \dfrac{12}{6}$

$\Delta x =2$

Hence;

$x_0 = 2 \\ \\ x_1 = 2+2 =4\\ \\ x_2 = 2 + 2(2) \\ \\ x_i = 2 + 2i$

Here, we are using left end-points, then:

$x_i-1 = 2+ 2(i-1)$

Replacing it into Riemann equation;

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} \begin {pmatrix}3 - \dfrac{1}{2} \begin {pmatrix} 2+2 (i-1) \end {pmatrix} \end {pmatrix}2$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2(i-1))$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2i-2)$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 -2i$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 2i$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - 2 \lim_{n \to \infty} \sum \imits ^{6}_{i=1} i$

Estimating the integrals, we have :

$= 6n - 2 ( \dfrac{n(n-1)}{2})$

= 6n - n(n+1)

replacing thevalue of n = 6 (i.e the sub interval number), we have:

= 6(6) - 6(6+1)

= 36 - 36 -6

= -6

5 0

3 years ago

A laptop computer is purchased for 2300 . After each year, the resale value decreases by 35% . What will the resale value be aft

denis-greek [22]

100-35 = 65
65% de 2300 = 1495 (mes 1)
2300-1495 = 805 (mes 2)
65% de 805 = 523,25 (mes 3)
65% de 523,25 = 340,1125 ~ 340,10 (mes 4)

8 0

3 years ago

Solve for n: 3(2−8n)=3n+6 Select one: -15 5 -5 0

Len [333]

N=0 bc you remove the parentheses, cancel the equal terms what would be 6 being cancel it would look like -24n=3n now and move the variable to the left collet like terms and then you will divide the sides. Your answer is 0

5 0

3 years ago