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1 year ago

In questions 6 – 9, state the solutions for the quadratic equation depicted in the graph.

Mathematics

1 answer:

Mariana [72]1 year ago

3 0

Step-by-step explanation:

It is just where it crosses the x axis

6) -3, -4

7) 1, -6

8) -5, -6

9) 3, -2.5

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How do you solve 7/8+(4/8-2/4)

SCORPION-xisa [38]

The answer is 7/8 find a common denominator or cross multiply

4 0

2 years ago

Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

alex41 [277]

Answer: $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

Step-by-step explanation:

Given two upward facing parabolas with equations

$y=6x^2 & y=x^2+2$

The two intersect at

$6x^2=x^2+2$

$5x^2=2$

$x^2$ = $\frac{2}{5}$

x= $\pm \sqrt{\frac{2}{5}}$

area enclosed by them is given by

A= $\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx$

A= $\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx$

A= $4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]$

A= $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

7 0

3 years ago

What is the area of the white boarder? 2cm 8cm 9cm 15cm

antiseptic1488 [7]

do you have a picture of the border?

8 0

3 years ago

Read 2 more answers

Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0

erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

$15x^2-kx+1=0$ (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

$2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8$

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

$15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}$

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0

3 years ago

1. Is the square root of 2 between 1.3 and 1.4? How do you know?

VikaD [51]

Answer:

Step-by-step explanation:

1st . 1.3^2= 1.69

1.4^2= 1.96

It's not bettween 1.3 & 1.4

2. 1.4^2=1.96

1.5^2= 2.25

it's betteen 1.4 & 1.5

3 . 1.4 & 1.5 so it's eqaul 1.4

3 0

3 years ago

Read 2 more answers