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mojhsa [17]
3 years ago
11

Given that BDFHJ ~ QSUWY, what is YQ?

Mathematics
2 answers:
valentinak56 [21]3 years ago
7 0
Took the test. Its D. Here are the others.

Given ΔDGK ∼ ΔMRQ, what is MQ?


its 27



Given ∆STC<span> ~ ∆</span>WBL<span>, what is </span>WL?

The answer is 24

Given ΔBEJ<span> ∼ Δ</span>RUW<span>, what is </span>RU<span>?
</span>

answer: 34

<span>Which polygons are similar?
</span>

The answer is the actual polygon, C.


Mark me brainiest! :D


Artyom0805 [142]3 years ago
5 0
YQ/SQ = JB/DB
YQ/72 = 60/45
YQ = 72*(60/45) = 96

Selection D is appropriate.
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Step-by-step explanation: Simplify the expression.

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Write 5 numbers that round to 740 when rounded to the nearest 10
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4 0
3 years ago
What is the probability that he will hit fewer than 8 of the bottles?
torisob [31]

Using the binomial distribution, it is found that the probability that he will hit fewer than 8 of the bottles is of 0.012, given by option A.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • The probability of a bottle being hit is of p = 0.95.
  • There are n = 10 bottles.

The probability that he hits fewer than 8 of the bottles is given by:

P(X < 8) = 1 - P(X \geq 8)

In which:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.95)^{8}.(0.05)^{2} = 0.0746

P(X = 9) = C_{10,9}.(0.95)^{9}.(0.05)^{1} = 0.3151

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

Hence:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.0746 + 0.3151 + 0.5987 = 0.988

P(X < 8) = 1 - P(X \geq 8) = 0.012

The probability that he will hit fewer than 8 of the bottles is of 0.012, given by option A.

More can be learned about binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
2 years ago
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