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3 years ago

Given that BDFHJ ~ QSUWY, what is YQ?

Mathematics

2 answers:

valentinak56 [21]3 years ago

7 0

Took the test. Its D. Here are the others.

Given ΔDGK ∼ ΔMRQ, what is MQ?

its 27

Given ∆STC ~ ∆WBL, what is WL?

The answer is 24

Given ΔBEJ ∼ ΔRUW, what is RU?


answer: 34

Which polygons are similar?


The answer is the actual polygon, C.

Mark me brainiest! :D

Artyom0805 [142]3 years ago

5 0

YQ/SQ = JB/DB
YQ/72 = 60/45
YQ = 72*(60/45) = 96

Selection D is appropriate.

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Elan Coil [88]

The answer would be a

8 0

3 years ago

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you have a full cylindrical glass of water that stands 8 inches tall and has a radius of 1.5 inches .if you pour the water into

Romashka-Z-Leto [24]

Volume of cylinder=πr²h volume of another cylinder=πr²h
=22/7×1.5×1.5×8 =22/7×2.5×2.5×12
=396/7 =1560/7
=56.57 =235.71

=235.71-56.57
=179.14 amount of water is able to hold by the larger cylinder

4 0

3 years ago

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Tom pays $1506 in rent every month. This amount is $50 more than twice what his brother Arturo pays for

Talja [164]

Answer:

$3062

Step by Step Explanation:

Arturo's rent can also be written as an expression

2t + 50

This is basically showing that two of Tom's rent plus $50 gives you his brother's rent.

So 2(1506) + 50

3012 + 50

3062

3 0

2 years ago

The Olympic-size pool at the recreational center is a right rectangular prism 50m long and 25m wide.The pool contains 3000m3 of

Andru [333]

Answer:

depth of swimming pool = 2.4 meters

Step-by-step explanation:

Volume of the swimming pool = l x b x h = 3000

Volume of the swimming pool = 50 x 25 x h = 3000

h = 2.4 meters

6 0

3 years ago

How to find the minimum value of f(x) = 3x (x - 4)?

DaniilM [7]

well, let's first off, expand the expression, 3x(x-4) => 3x²-12x, which we can also write as

f(x) = 3x² - 12x + 0

now, this is a quadratic equation with a leading term with a positive coefficient, namely its graph is a parabola, or a Cup-Shaped figure, so the graph comes from the top, goes down down down, reaches a U-turn, then goes back up up up.

the U-turn, or vertex of the quadratic, is the lowest point in the "cup".

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ \stackrel{f(x)}{y}=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{-12}x\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{(-12)}{2(3)}~~,~~0-\cfrac{(-12)^2}{4(3)} \right)\implies \left( \cfrac{12}{6}~,~0-\cfrac{144}{12} \right)\implies (2~,~-12)$

4 0

3 years ago