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Greeley [361]
2 years ago
11

A man with 5 keys wants to open his door and tries the keys at random. Exactly one key will open the door. Determine the probabi

lity distribution of random variable X if X is the number of trials required to open the door. Assume that unsuccessful keys are NOT eliminated from future trial.
Mathematics
1 answer:
Scrat [10]2 years ago
3 0

Answer:

Step-by-step explanation:

Given that a man with 5 keys wants to open his door and tries the keys at random.

Exactly one key will open the door.

Assume that unsuccessful keys are NOT eliminated from future trial.

So the probability of choosing correct key = 0.2 = constant since unsuccessful key is not eliminated

X = no of trials required to open the door

We find that X is discrete taking values 1,2....infinity because there is a chance that continuously unsuccessful keys are drawn

P(X=x) = Prob that x-1 trials are unsuccessful and xth trial is successful

=0.8^{x-1} (0.2), x=1,2.....

is the pdf of X

This is a Geometric distirbution.

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2 years ago
1. Split the biconditional into two conditionals: Zipzorps
bagirrra123 [75]

Answer:

Conditional: If ZipZorps are jumpy, then Flygers are therapeutic.

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Step-by-step explanation:

ZipZorps are jumpy.

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These are the 2 statements.

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8 0
3 years ago
Carla has already written 10 pages of a novel. she plans to write 15 additional pages per month until she is finished. write and
grin007 [14]
Linear Equation: 15m+10=w
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4 0
3 years ago
what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base
JulsSmile [24]

Answer :

  • 301.44 cm³

⠀

Explanation :

We know,

{ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}

Where,

  • <em>r</em> is the radius of the cylinder. Here, the radius is 4 cm

  • <em>h</em> is the height of the cylinder. Here, height is 6 cm

  • Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}

⠀

{ \longrightarrow \qquad{ \ {  \it{ \pmb{ Volume_{(cylinder)}  {= 301.44 \: }}}}}}

⠀

Therefore,

  • The volume of the cylinder is 301.44 cm³ approximately.
6 0
2 years ago
Read 2 more answers
Please help me... I don’t understand this at all...
timama [110]
For the problem in the upper left corner, see "figure 1"

For the problem in the upper right corner, see "figure 2"

For the problem in the lower left corner, see "figure 3"

For the problem in the lower right corner, see "figure 4"

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2 years ago
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