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3 years ago

In a school there are 60 teachers and 1200 students. 30% of students are bilingual

2 answers:

6 0

First, you need to find out what 15% of 60 is. So you do 60×0.15 and that is 9. Then you do 1200×0.3, and that is 360. So, you add both of the final mini answers, and you get 369 people are bilingual

Lera25 [3.4K]3 years ago

5 0

The are 369 altogether. 360 students and 9 teachers.

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Help please & thank you , need it asap

lapo4ka [179]

Answer:

x = 180 - 30 - 41 - 67 = 42°

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2 years ago

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Write in slope-intercept form an equation of the line that passes through the given points.

nlexa [21]

Answer: y = 1/ 8 x − 1

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3 years ago

Check all that apply. If csc =13/5 , then:

nirvana33 [79]

Answer:

The answer are the options B and C

$sin(x)=\frac{5}{13}$

$tan(x)=\frac{5}{12}$

Step-by-step explanation:

we know that

$csc(x)=\frac{1}{sin(x)}$

In this problem we have

$csc(x)=\frac{13}{5}$

substitute

$\frac{13}{5}=\frac{1}{sin(x)}$

solve for sin(x)

$sin(x)=\frac{5}{13}$

$cos^{2}(x)+sin^{2}(x)=1$

substitute the value of sin(x) and solve for cos(x)

$cos^{2}(x)+(\frac{5}{13})^{2}=1$

$cos^{2}(x)=1-(\frac{5}{13})^{2}$

$cos^{2}(x)=(\frac{13^{2}-5^{2}}{13^{2}})$

$cos^{2}(x)=(\frac{144}{13^{2}})$

$cos^{2}(x)=(\frac{12^{2}}{13^{2}})$

$cos(x)=(\frac{12}{13})$

The function tangent is equal to

$tan(x)=\frac{sin(x)}{cos(x)}$

substitute the values

$tan(x)=\frac{(5/13)}{(12/13)}=5/12$

8 0

3 years ago

Read 2 more answers

you have 32 tbsp of peppercorns you need 2 teaspoons to make one serving of cajun seasoning how many servings can u make

suter [353]

Answer:

48 servings

Step-by-step explanation:

3tsp=tbsp

32*3=96

96/2=48

8 0

1 year ago

9)<br> 5.6 yd<br> 5 yd<br> 12 yd<br> Find the area. (A = 1/2 ( 61 + b2) h)

krek1111 [17]

Answer:

Area, A = 63.6 square yards

Step-by-step explanation:

A trapezoid refers to a quadrilateral that is convex in shape; as such it has no equal sides and no parallel sides.

Let the height of a trapezoid be h.

Let the top base of a trapezoid be b1.

Let the bottom base of a trapezoid be b2.

$Area \; of \; trapezoid = \frac {1}{2} * (Sum \; of \; nonparallel \; sides) * height$

Therefore, $Area \; of \; trapezoid = \frac {1}{2} * (b_{1} + b_{2}) * h$

Given the following data;

Length, b1 = 5 yards

Width, b2 = 5.6 yards

Height, h = 12 yard

To find the area of geometrical shape (trapezoid), we would use the above formula;

A = 1/2 (b1 + b2) * h

Substituting into the formula, we have;

A = ½ * (5 + 5.6) * 12

A = ½ * (10.6)*12

A = 5.3 * 12

Area, A = 63.6 square yards

8 0

2 years ago