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stepan [7]
3 years ago
7

How do you solve this problem?

Mathematics
1 answer:
MAXImum [283]3 years ago
6 0
Easy here OK so what you do is multiply 2 times 6 and it is 12 then do 2 times 12 which is 24 so Tanya is 24 hope I helped!
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Help please I’m confused
kipiarov [429]

Answer:

h = 5.4

Step-by-step explanation:

Basically these are 2 similar triangles. That means:

Corresponding sides are proportional.

We can set up a ratio of each triangle separately and equate, cross multiply and solve for "h".

h corresponds to 2.4

2.9 corresponds to 1.3

Setting up the ratio and solving for h:

\frac{h}{2.4}=\frac{2.9}{1.3}\\1.3h=2.4*2.9\\1.3h=6.96\\h=\frac{6.96}{1.3}\\h=5.35

Rounded to 1 decimal place,

h = 5.4

7 0
3 years ago
First term is is 22 and the common difference is -13
bonufazy [111]

Answer:

a_{n} = 35 - 13n

Step-by-step explanation:

Assuming you require the n th term formula

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n- 1)d

where a₁ is the first term and d the common difference

Here a₁ = 22 and d = - 13, thus

a_{n} = 22 - 13(n - 1) = 22 - 13n + 13 = 35 - 13n

8 0
3 years ago
What is the area of this polygon?
brilliants [131]

The area of this polygon is 35.5 units∧2.

Good luck!!!!



8 0
3 years ago
Read 2 more answers
What is the y-intercept of a line that has a slope of One-fourth and passes through point (8, 3)?
kondor19780726 [428]

Answer:

y-intercept is (0, 1)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
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