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3 years ago

8% of what number is 16

Mathematics

2 answers:

aliina [53]3 years ago

7 0

200, because 8% is 8 parts of 100%. Then 1 part of that 100% is 16/8=2. Then 100% is the number i.e; 200

xz_007 [3.2K]3 years ago

4 0

8% of 100, is 16/8 is, 2 times 100 is 200

Answer: 200

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Find the area of the figure.

irina [24]

Where is the figure?

6 0

3 years ago

Stephine puts 30 cubs in a box. The cubes are 1/2 inch on each side. The box holds 2 layers with 15 cubes in each layer.

mixas84 [53]

Answer:

3 3/4 cubic inches,

Step-by-step explanation:

Stephanie puts 30 cubes in a box. The cubes are 1/2 inch on each side. The box holds two layers with 15 cubes in each layer. What is the volume of the box awnsers 5cubic inches, 7 1/2 cubic inches,3 3/4 cubic inches, 15 cubic inches.

✓From the question we are informed that Stephanie puts 30 cubes in a box. The cubes dimension are 0.5 inch on each of the sides.

✓ Since the sides is 0.5inch each, the volume is (0.5×0.5×0.5) The volume of one cube = (0.5 inch)³ = 0.125 inch³

✓ we can calculate the Volume of 30 cubes as

[ 30 cubes in a box × 0.125 inch³]

= 3.75 inch³

✓ 3.75 inch³ can be converted into fraction as (3 3/4) inch³ which is the third Option.

5 0

3 years ago

Maya is packing her backpack for hike. In one pocket, she puts in a 1/2 pound bag of trail mix,a water bottle weighing 2 1/8 pou

Rudik [331]

Total weight of three items is 2.875 pounds

Solution:

Given that,

Maya is packing her backpack for hike

From given,

$pound\ bag\ of\ trail\ mix = \frac{1}{2}\ pounds$

$water\ bottle = 2\frac{1}{8}\ pounds = \frac{17}{8}\ pounds\\\\flashlight = \frac{1}{4}\ pounds$

How much weight do these three items add to her backpack?

Add all these together

$Total\ weight = \frac{1}{2} + \frac{17}{8} + \frac{1}{4}\\\\Total\ weight = \frac{1 \times 4}{2 \times 4} + \frac{17}{8} + \frac{1 \times 2}{4 \times 2}\\\\Total\ weight = \frac{4}{8} + \frac{17}{8} + \frac{2}{8}\\\\Total\ weight = \frac{23}{8} = 2.875$

Thus total weight of three items is 2.875 pounds

7 0

3 years ago

The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction

Len [333]

Answer:

(a) n : 20 50 100 500

P (-200 < X - μ < 200) : 0.2886 0.4444 0.5954 0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable X represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, μ = $16,642 and standard deviation is, σ = $2,400.

Assuming that the random variable X follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

For a sample size of n = 20

$P(\mu-200$

$=P(-0.37$

For a sample size of n = 50

$P(\mu-200$

$=P(-0.59$

For a sample size of n = 100

$P(\mu-200$

$=P(-0.83$

For a sample size of n = 500

$P(\mu-200$

$=P(-1.86$

n : 20 50 100 500

P (-200 < X - μ < 200) : 0.2886 0.4444 0.5954 0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample ( $\bar x$ ) approaches the whole population mean ( $\mu_{x}$ ).