2-3(z-5)+11=4
<em>Distribute</em>
2-3z+15+11=4
<em>Move the constants to gether but make sure they keep thei signs</em>
2+15+11-3z=4
<em>Simplify</em>
28-3z=4
<em>Start to Isolate the variable by subtracting </em>28<em> from </em><u><em>both</em></u><em> sides of the equation</em>
-3z=-24
<em>Completely isolate the variable by deviding the </em><u><em>whole</em></u><em> equation by </em>-3
z=8
<u><em>If you would like anything explained, just ask</em></u>
Answer:
1250 amps
Step-by-step explanation:
V = 5000 V
R = 4 ohms
Use ohms law: V = IR
5000 =I(4)
I = 1250 amps
Answer:
-30x^2 sqr2x
Step-by-step explanation:
The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².
The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines
b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm
Call b the base of this triangle.
The vertex angle is 120°, so the other two angles have measure θ such that
120° + 2θ = 180°
since the interior angles of any triangle sum to 180°. Solve for θ :
2θ = 60°
θ = 30°
Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find
tan(30°) = h / (b/2) ⇒ h = 48 cm
Then the area of the triangle is
1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²
and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:
3072π cm² - 2304√3 cm² ≈ 5660.3 cm²
2+2 = 4. Bro it was so hard. Did i helped you?
