The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Answer: $789.74
$584.99 x35% = 204.75
584.99 + 204.75= 789.74 the original price
Step-by-step explanation:
Answer:
System 1 : {3,0}; System 2 : {6,-2}
Step-by-step explanation:
2x + 3y = 6
-2x - y = -6
2y = 0
y = 0
-2x = -6
x = 3
system 2
2x + 3y = 6
2x + 2y = 8
y = -2
2x -4 = 8
2x = 12
x = 6
Expanded:5,000,000+300,000+20,000+5,000+600+3+0.7+0.01+0.002
Word: five million, three hundred twenty-five thousand, six hundred three and seven hundred twelve thousandths
So she started at 12 and ended at 14
14-12=2
she traveled for 2 hours
50miles per hour or 50m/h
(m=miles not minutes)
2 hours so
2h times 50m/h
100miles traveled