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KengaRu [80]
3 years ago
8

Can soneone help me with these basic vector math problems?!

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

Yes you are right on both.

Step-by-step explanation:

Plz make brainliest

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Can you explain how you got the answer as well please?
Vikki [24]

Answer:

A. 35

Step-by-step explanation:

The total amount of movies that the critic rates that we are given is 20. Now they want to figure us to figure it out with 100 movies. 20 times 5 is one hundred. We are supposed to look at the 3 star reviews, which is 7 movies. 7 times 5 is 35. Hope this helps!

5 0
2 years ago
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Smooth, suave, ingratiatingly pleasant
mash [69]
I say the answer is B. Bland

4 0
3 years ago
Simplify 4x + 8y - 3x + 2y
mezya [45]

Answer: 4x-3x, and 8y+2y. x+10y is the equation in simplest form.

Step-by-step explanation:

Step 1. You need to combine like terms:

 4x-3x, and 8y+2y. x+10y would make the equation( 4x + 8y - 3x + 2y) in simplified form.

Hope I could help! :)

7 0
3 years ago
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1) h(x)=3x3<br>g(x)= - 4x+1<br>Find (h+g)(10)​
Aleksandr-060686 [28]

Answer:

(h+g)(10) = 2691

Step-by-step explanation:

h(x) = 3x^3\\g(x) = -4x+1

Adding both equations will make it:

(h+g)(x) = 3x^3-4x+1

Putting x = 10 will make it:

(h+g)(10) = 3(10)^3-4(10)+1

= 3(1000)-40+1

= 3000-39

= 2961

3 0
3 years ago
Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)
Arlecino [84]
y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt

By the fundamental theorem of calculus,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}

Now the arc length over an arbitrary interval (a,b) is

\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx

But before we compute the integral, first we need to make sure the integrand exists over it. x^{3/2} is undefined if x, so we assume a\ge0 and for convenience that a. Then

\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)
6 0
3 years ago
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