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Scilla [17]
3 years ago
6

Circle 1 is centered at (−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1) and has a radius of 6 centimet

ers. What transformations can be applied to Circle 1 to prove that the circles are similar? Enter your answers in the boxes. The circles are similar because you can translate Circle 1 using the transformation rule ( , ) and then dilate it using a scale factor of
Mathematics
1 answer:
IgorC [24]3 years ago
3 0
Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?

To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).

Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.

Translations and dilations (along with reflections and rotations) belong to a group known as transformations.
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The coordinates of the 3 of the vértices of a parallelogram are (-7, 3), (-6, 1), and (-4, 5). What is the equation for the line
Natali [406]

We know, opposite sides are parallelogram is parallel, therefore slopes are equal.

Slope of line one :

m=\dfrac{-7-(-6)}{3-1}\\\\m =\dfrac{-1}{2}\\\\m= -0.5

So, equation of other line passing through (-4,5) and have slope of -0.5 is :

y-5 = -0.5( x-(-4))

y-5 = -0.5x - 2

y  + 1/2x = 3

2y + x = 6

Therefore, equation of line containing the (-4, 5) is 2y + x = 6.

Hence, this is the required solution.

6 0
3 years ago
Find an equation of the line that satisfies the given condition. (Let x be the independent variable and y be the dependent varia
NeTakaya

Answer:

y = 4

Step-by-step explanation:

  • A line parallel to the x-axis has the same value of the <em>dependent variable (y)</em> for all the values of the <em>independent variable (x)</em>.  Hence, the line would be an <u>horizontal line that  passes through the y-axis and never meets the x-axis</u>. Since this line satisfies the condition of passing through the coordenates (x,y), (-6,4), then the equation is equal to the value of the coordinate y.  

 

Therefore, the equation of a line that satisfies these two conditions is <em>y = 4</em>.

Download pdf
8 0
3 years ago
Given that lines a and b are parallel, what angles formed on line b when cut by the transversal are congruent with ∠2?
Kruka [31]

Answer:

The angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

Step-by-step explanation:

Consider the provided information.

If transversal line crossed by two parallel lines, then, the corresponding angles and alternate angles are equal .

The angles on the same corners are called corresponding angle.

Alternate Angles:  Angles that are in opposite positions relative to a transversal intersecting two lines.

∠2 and ∠6 are corresponding angles

Therefore, ∠2 = ∠6

∠2 and ∠7 are alternate exterior angles

Therefore, ∠2 = ∠7

Hence, the angles formed on line b when cut by the transversal are congruent with ∠2 are \angle{6}\text{ and }\angle{7}

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3 years ago
If f(x)=2x+1 and g(x)=(x^2)-7, find (f/g)(x).
alexdok [17]

f(x)=2x+1;\ g(x)=x^2-7\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\boxed{\left(\dfrac{f}{g}\right)(x)=\dfrac{2x+1}{x^2-7}}

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Answer:

Practice the worksheet on word problem on addition and subtraction.

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