Answer:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:
For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Step-by-step explanation:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:
For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Answer:
A = bh = (17 km)(11 km) = 187 km^2
The <u>correct answer</u> is:
0.14.
Explanation:
We are asked "Given that Lorenzo paid more than $30 for a ticket, what is the probability that he purchased the ticket at the box office?"
Using the conditional relative frequency table, we start at the column "More than $30". We then go to the row "Purchased at the Box Office." The value in this cell is 0.14; this is the probability.
Answer:
The correct answer is C.
Step-by-step explanation:
First, we can eliminate A and D since it is obviously only 36 months.
Note that the question asks what can be interpreted from the <em>range</em> of the graph.
The range is the number of users in thousands (per month) (as can be seen from the side title).
While B is technically correct, it wrongly interprets the range. C is the best choice.
The correct answer is C.
Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is 
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
