Ok so these are the first 3 hope its clear
Answer:
a) 47.55
b) 58
c) 47.88
Step-by-step explanation:
Given that the size of the orders is uniformly distributed over the interval
$25 ( a ) to $80 ( b )
<u>a) Determine the value for the first order size generated based on 0.41</u>
parameter for normal distribution is given as ; a = 25, b = 80
size/value of order = a + random number ( b - a )
= 25 + 0.41 ( 80 - 25 )
= 47.55
<u>b) Value of the last order generated based on random number (0.6)</u>
= a + random number ( b - a )
= 25 + 0.6 ( 80 - 25 )
= 25 + 33 = 58
<u>c) Average order size </u>
= ∑ order 1 + order 2 + ----- + order 10 ) / 10
= (47.55 + ...... + 58 ) / 10
= 478.8 / 10 = 47.88
Answer:
Answers are 20, 12 and 16
Step-by-step explanation:
Y=4x
for x = 5
y=4(5)
y=20
for x = 3
y=4(3)
y=12
for x = 4
y=4(4)
y=16
On google, it says 8.463.
You must realize that it depends on the function ...
something that you've kept hidden from us.
