Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula

where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,

or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
Step-by-step explanation:
1. -35, 2
2. -72, -6
3. -16, 0
4. 40, 13
5. -15, 2
6. -30, 7
7. 30, 11
8. 42, -13
9. -3, -24
10. -4, 20
11. 7, 1
12. 4, -24
13. -7, -70
14. 4, 9
15. 7, -3
16. 9, 3
17. -10, 11
18. 6, -5
19. 11, 6
20. 1, -9
21. -9, 4
22. -8, 7
23. 6, 4
24. -7, -5
25. 11, 4
26. 10, 3
27. -8, 5
28. -9, 0
I believe the answer is $33.60?
the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3
5*x^3 - (4x/3)
Answer:
It is 7 2/11 is less then 7 4/10
Step-by-step explanation:
You do not have to worry about the whole number because they are the same. You have to compare the fractions, so if comparing fractions 10 is less then 11 so 1/10 has a larger space then 1/11. That is how i got the answer. Hope this helps. Am I right?