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3 years ago

6

A An airplane descends 75 feet each minute after reaching an altitude of 24,580 feet. what is the airplane's altitude after 45 m

inutes?

2 answers:

QveST [7]3 years ago

4 0

You have to multiply 75 x 45 which is 3,375. Then, you subtract 24,580 - 3,375 which is 21,205. Hope this helped. :)

padilas [110]3 years ago

4 0

24,580-(75m) m=45 24,580-(75(45) 24,580-3,375=21,205 feet

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What is 300+45-9x2+22-1+2

valentinak56 [21]

Answer:

350

Step-by-step explanation:

Use PEMDAS.

$300+45-9*2+22-1+2$

300+45-18+22-1+2

345-18+22-1+2

327+22-1+2

349-1+2

348+2

350

8 0

3 years ago

Find the equation of the line parallel to the graph of 7x-3y=21 that has an x-intercept of -1.

zhuklara [117]

To start this, you would have to get y by itself to have an equation you can graph. Start by subtracting 7x from both sides.
-3y= -7x+21
Next, divide both sides by -3
y = 7/3x + 7
A parallel line would have the same slope of 7/3x. Since you need to have an intercept of -1 the equation would be y = 7/3x -1

8 0

4 years ago

Can you show your work for this 4m-5(3m+10)=126

earnstyle [38]

Answer:

m=−16

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4m−5(3m+10)=126

4m+(−5)(3m)+(−5)(10)=126(Distribute)

4m+−15m+−50=126

(4m+−15m)+(−50)=126(Combine Like Terms)

−11m+−50=126

−11m−50=126

Step 2: Add 50 to both sides.

−11m−50+50=126+50

−11m=176

Step 3: Divide both sides by -11.

−11m /−11 = 176 /−11

m=−16

4 0

3 years ago

Plz help me!!!!

stich3 [128]

So we have the exponential equation: $y=18582(0.90)^x$
where
$y$ is the number of visitors
$x$ are the weekends since opening

1. Since the opening weekend is the day of the the park's opening, we just need to replace $x$ with $0$ in our exponential equation to get the number of visitors on the opening weekend:
$y=18582(0.90)^x$
$y=18582(0.90)^0$
$y=18582(1)$
$y=18582$

We can conclude that there were 18582 visitors on the opening weekend.

2. Just like before, to find the approximate number of visitors on the ninth weekend, we just need to replace $x$ with $9$ in our exponential equation:
$y=18582(0.90)^x$
$y=18582(0.90)^9$
$y=7199.0475$
And rounded to the nearest integer:
$y=7199$

We can conclude that there were approximately 7199 visitors on the $9^{th}$ weekend.

3. Here we know that the number of visitors is 15051. Since $y$ represents the number of visitors, we just need to replace $y$ with 15051 in our exponential equation and solve for $x$ :
$y=18582(0.90)^x$
$15051=18582(0.90)^x$
$\frac{15051}{18582} =0.90^x$
$0.90^x= \frac{5017}{6194}$
$ln(0.90^x)=ln(\frac{5017}{6194})$
$xln(0.90)=ln(\frac{5017}{6194})$
$x= \frac{ln(\frac{5017}{6194})}{ln(0.90)}$
$x=2.0002$
And rounded to the nearest whole number:
$x=2$

We can conclude that the number of visitors was about 15,051 after 2 weekends.

4 0

3 years ago

I need help with this asap

Pachacha [2.7K]

I think the answer would be the first or last one

6 0

3 years ago