Let's say the length is L, and the width is W
L is one foot more than 2W, so L=1+2W
the area of the rectangle: A=L*W=300
replace L with 1+2W: (1+2W)*W=300 =>2W^2+W-300=0
solve the quadratic equation: (W-12)(2W+25)=0
W=12 or W=-12.5 (impossible)
so the width is 12, and the length is L=1+2*12=25
please refer to this website for how to factor a quadratic equation
http://www.purplemath.com/modules/factquad.htm
Answer:
11.25
Step-by-step explanation:
Answer:
6.4 minutes or 384 seconds
X = -20p + 500
20p = 500 - x
p = (500 - x)/20
R = xp = x(500 - x)/20 = (500x - x^2)/20
