The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
3
------------
4(5z+16)
I'm assuming you want to include all of the numbers
Answer:
option b
Step-by-step explanation:
replace x and y with the x and y of the ordered pair
option a: 2(4)+4(5)=6(4)-5
solve
8+20=24-5
28=19 not true
option b:2(5)+4(4)=6(5)-4
solve
10+16=30-4
26=26 true
Radius ^2 * pi = 1 pizza * 2 = area of 2 pizzas = 307.876 in ^2
Correct Answer:
Option 3: <span>The quadratic function has two distinct real zeros.
The function is quadratic, therefore it can have only 2 zeros. The knowledge of x-intercepts is needed to determine the zeros, y-intercepts has nothing to do with the zeros of a function. The given function has 2 unique x-intercepts, so according to the fundamental theorem of algebra, this function has 2 distinct real roots as number of distinct real roots are equal to the number of x-intercepts. Therefore, option 3 is the correct answer. </span>
