Answer:
Men's Hyper Jade/Frosted is is $9.89, or $9.90 rounded up.
Spruce/Barely Volt is $12.37, or $12.40 rounded up.
Step-by-step explanation:
Answer:
100.9 yards
Step-by-step explanation:
One circuit of the track is a distance of ...
C = 2πr = 2π(60 yd) = 120π yd.
At Alex's running rate, the distance covered in 20 minutes is ...
(4 yd/s)(20 min)(60 s/min) = 4800 yd
The number of circuits will be ...
(4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits
The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,
That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd
The shortest distance along the track to Alex's starting point is about 100.9 yards.
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<em>Additional comment</em>
The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.
Answer:
15 cm
Step-by-step explanation:
A= base x height
![\frac{1500cm^{3} }{100 {cm}^{2} } \\ = 15cm](https://tex.z-dn.net/?f=%20%5Cfrac%7B1500cm%5E%7B3%7D%20%7D%7B100%20%7Bcm%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%2015cm)
Responder:
x = 42,4
Explicación paso a paso:
Podemos encontrar el valor de x ya que no se nos dice qué buscar
La suma de dos ángulos suplementarios es 180 grados, por lo tanto;
2x - 14 + 3x - 18 = 180
2x + 3x - 32 = 180
5 veces = 180 + 32
5 veces = 212
x = 212/5
x = 42,4
Por tanto, el valor de x es 42,4
One <em><u>possible answer </u></em>is:
Draw segments from P to R and from P to Q; the triangles formed will be congruent by the SAS congruence theorem.
Explanation:
Drawing segments from P to R and from P to Q creates triangles PSR and PSQ.
In these two triangles, we know that RS ≅ SQ and PS≅PS.
Since PS is the perpendicular bisector of RQ, we also know that ∠PSR = 90; this is the same as ∠PSQ, so the two angles are congruent.
This means we have two sides and the angle between them congruent; this is the SAS postulate, which proves the triangles are congruent.
Since the triangles are congruent, all corresponding sides are congruent; this means that PR ≅ PQ.