X+3=24x :)))))))))))))))))))))
This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.
Each AP class counts twice and counts as 2 classes.
Class Ben's grade Points Number of Classes
AP English B 3 + 3 2
AP Government B 3 + 3 2
AP Algebra II A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8
GPA = (total points)/(number of classes) = 24/8 = 3
<span>Answer: B 3.0</span>
Answer:
Contradiction
Step-by-step explanation:
Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.
So,
If the number in the ten-thousandth's place is greater than or equal to 5, then round up. If not, round down.
0.1325: Note the 5. We round up.
0.1325 --> 0.133
