All categories

3 years ago

If a baking tray is 500mm by 700mm, how many of 25cm in diameter can fit into the oven

2 answers:

8 0

<span>500 x 700 = 350,000 mm^2 Next, you must find the area of the "circles" or "cakes". 3.14r^2 3.14(25^2) 3.14(625) 1962.5 mm^2 Finally, you will have to divide the area of the baking tray by the area of the circle/cake. 350,000/1962.5 178.34 cakes So, your final answer will be.... Approx 178 circles/cakes can fit in the oven. Hope this helps! Cami</span>

irakobra [83]3 years ago

5 0

First you need to find the area of the baking tray. 500 x 700 = 350,000 mm^2 Next, you must find the area of the "circles" or "cakes". 3.14r^2 3.14(25^2) 3.14(625) 1962.5 mm^2 Finally, you will have to divide the area of the baking tray by the area of the circle/cake. 350,000/1962.5 178.34 cakes So, your final answer will be.... Approx 178 circles/cakes can fit in the oven. Hope this helps! Cami

You might be interested in

I need some help with this

natima [27]

Answer:

Step-by-step explanation:

8 0

3 years ago

-11+3(b+5)=7 what is b

evablogger [386]

Answer:

b=1

Step-by-step explanation:

-11+3(b+5)=7

-11+3b+15=7

-11+15+3b=7

4+3b=7

3b=7-4

3b=3

3b/3=3/3

b=1

hope it's helpful

8 0

2 years ago

Read 2 more answers

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$