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4 years ago

Which list is in order from least to greatest?

Mathematics

2 answers:

Sergio039 [100]4 years ago

8 0

Answer:

Picture a number line: The farther to the left, the smaller the number

The farther to the right, the larger the number

Step-by-step explanation:

9/5,−2.5,−1.1,−4/5, 0.8

9/5 = 1.8

-4/5 = -0.8

On number line from left to right these are:

-2.5, -1.1, -4/5, 0.8, 9/5

So that is the order from least to greatest

<----*---------*------*------|------*-------*--------->

-2.5 -1.1 -4/5 0 0.8 9/5

Reptile [31]4 years ago

4 0

Answer:

|−3.5| , |4.2|, |−9|

have a great day

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alekssr [168]

Answer:

$\bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}$

Step-by-step explanation:

$-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7$

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3 years ago

A snail move 6 feet every 10 hours. how far it does in 15 hours

Anna007 [38]

6 feet:10 hours

multiply by 1.5 on both sides

9 feet:15 hours

answer: 9 ft

4 0

4 years ago

Need help asap please

Ira Lisetskai [31]

Answer:

858 the next one is 947

Step-by-step explanation:

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3 0

3 years ago

5. Write two or three sentences that describe how a chart differs from a table. -please help meh T-T

igomit [66]

Answer:

Key difference: Tables represent facts and figures in a row and column format. Charts represent data in a more graphical manner which may include lines, bars and circles.

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3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago