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xxTIMURxx [149]
3 years ago
7

The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for larger vehicles. T

he amount collected can be modeled by the equation 5 x plus 10 y equals 800, where x represents the number of small vehicles and y represents the number of larger vehicles. If the number of larger vehicles washed was 60, how many small vehicles were washed in total?
40

100

-10

50


Answer quickly please, brainliest to who answers correctly! <3
Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

40

Step-by-step explanation:

Do 60 × 10.00 to get 600. Then do 800-600 to get 200. Then do 200÷5.00 to get 40.

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Lines s and t are perpendicular. If the slope of line s is -5, what is the slope of line ?
stiks02 [169]

Answer:

B: 1/5

Step-by-step explanation:

If the lines are perpendicular, they have negative reciprocal slopes

s has a slope of -5

t must have a slope of - (1/ -5)

                                    = 1/5

7 0
3 years ago
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I need help. Find X and Y
Jlenok [28]

Answer:

Y is 2 and x is 1

Step-by-step explanation:

If you subtract 3 and 1 you will get 2 so that is y and for x you do the same thing but backwards

7 0
4 years ago
Which number line shows the graph of -2.75 -3<br> -2<br> -1<br> 0<br> 1<br> 2<br> 3<br> 0<br> 1<br> 2.<br> 3<br> -3 -2<br> -1<br
nikklg [1K]

Answer:

I believe the answer is A, the first option.

Step-by-step explanation:

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4 0
3 years ago
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if emma spent $14.00 on jewerly and recieved $6.00 in change how much money did she spent . what equation could be used to find
rjkz [21]
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7 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
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