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2 years ago

I needd help someone help me out please

Mathematics

1 answer:

LiRa [457]2 years ago

6 0

Answer:

i will sure help you

Step-by-step explanation:

x=3

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How would you find the missing x and y values if you don’t have a model or equation to go by?

mamaluj [8]

You can find the slope and y-intercept, and make an equation in slope- intercept form and them just plug in the other x values in the equation.

3 0

3 years ago

I need the corresponding letters on the equation. A= B= C= D= E= F= G=

REY [17]

Answer:

A = 3

B = 1

C = 2

D = 10

E = 2

F = Not listed

G = 1

Step-by-step explanation:

$\sqrt[3]{270x^5y^7} =\sqrt[3]{27*10x^5y^7}=3xy^2\sqrt[3]{10x^2y}$

8 0

2 years ago

Find a homogeneous linear differential equation with constant coefficients whose general solution is given by

frez [133]

Answer:

$y" + 2y' + 2y = 0$

Step-by-step explanation:

Given

$y=c_1e^{-x}cosx+c_2e^{-x}sinx$

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

$y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)$

Where

$\alpha = -1$ and $\beta = 1$

For a homogeneous linear differential equation, the repeated value m is given as:

$m = \alpha \± \beta i$

Substitute values for $\alpha$ and $\beta$

$m = -1 \± 1*i$

$m = -1 \± i$

Add 1 to both sides

$m +1= 1 -1 \± i$

$m +1= \± i$

Square both sides

$(m +1)^2= (\± i)^2$

$m^2 + m + m + 1 = i^2$

$m^2 + 2m + 1 = i^2$

In complex numbers:

$i^2 = -1$

So, the expression becomes:

$m^2 + 2m + 1 = -1$

Add 1 to both sides

$m^2 + 2m + 1 +1= -1+1$

$m^2 + 2m + 2= 0$

This corresponds to the homogeneous linear differential equation

$y" + 2y' + 2y = 0$

6 0

3 years ago

Pls help me its due sooon

stira [4]

Answer:

nobody

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Find w. A. 8.9 B. 0.05 C. 0.08 D. 5.2

enyata [817]

Answer:

Step-by-step explanation:

Measure of angle V = 180 - 62 - 36 = 82 degrees

So by the law of sines, 10/sin(82 deg) = w/sin(62 deg)

w = [10sin(62)]/sin(82)

from here just plug this into a calculator

4 0

2 years ago