You guys pls help easy

Mathematics

1 answer:

pav-90 [236]3 years ago

3 0

Answer:

B = 1/2 h(b1+b2)

Step-by-step explanation:

Hope this helped :( ?

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Solve for the missing variable. Round to the nearest tenth.

Juliette [100K]

Answer:

x = 4
y ≈ 10.8

Step-by-step explanation:

In this geometry, the triangles are similar. That means corresponding sides are proportional:

short side/long side = x/10 = 10/25

x = 100/25 = 4 . . . . multiply by 10

hypotenuse/short side = y/x = (x+25)/y

y² = 4(29) = 116 . . . . . use 4 for x; cross multiply

y = √116 ≈ 10.8

3 0

3 years ago

4v² +2=0<br> how do you solve

BARSIC [14]

Answer:

idk

Step-by-step explanation:

6 0

4 years ago

Find the zero of each function and state the multiplicity of each zero. Please show all steps.

vodka [1.7K]

Answer:

1. y=(x+3)^3. Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.

3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.

Step-by-step explanation:

1. y=(x+3)^3

$y=0\\ (x+3)^3=0\\ \sqrt[3]{(x+3)^3}=\sqrt[3]{0}\\ x+3=0\\ x+3-3=0-3\\ x=-3$

Zero: x=-3 multiplicity 3.

2. y=(x-2)^2 (x-1)

$y=0\\ (x-2)^2(x-1)=0\\ \left \{ {{(x-2)^2=0} \atop {x-1=0}} \right\\ \left \{ {{\sqrt{(x-2)^2} =\sqrt{0} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x-2=0} \atop {x=1}} \right\\ \left \{ {{x-2+2=0+2} \atop {x=1}} \right\\ \left \{ {{x=2} \atop {x=1}} \right.$

Zeros: x=2 multiplicity 2; x=1 multiplicity 1

3. y=(2x+3)(x-1)^2

$y=0\\ (2x+3)(x-1)^2=0\\ \left \{ {{2x+3=0} \atop {(x-1)^2=0}} \right\\ \left \{ {{2x+3-3=0-3} \atop {\sqrt{(x-1)^2} =\sqrt{0} }} \right\\ \left \{ {{2x=-3} \atop {x-1=0}} \right\\ \left \{ {{\frac{2x}{2} =\frac{-3}{2} } \atop {x-1+1=0+1}} \right\\ \left \{ {{x=-\frac{3}{2} } \atop {x=1}} \right.$