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3 years ago

Pythagorem theoem helppp idk what to do

Mathematics

2 answers:

Lemur [1.5K]3 years ago

8 0

i think could it be 12.5?

Afina-wow [57]3 years ago

6 0

Hope this helps comment if it needs more detail.

You might be interested in

For what value of x is the following quadrilateral a parallelogram?

Natasha_Volkova [10]

2x-9 = x+8

2x-9-x=8

2x-x = x

x-9=8

x = 9+8

x=17

6 0

3 years ago

Y=x.arctan(x)^1/2. find dy/dx. pls show steps

Whitepunk [10]

$y=x(\arctan x)^{1/2}$

Use the product rule first:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

Use the chain rule to compute the derivative of $(\arctan x)^{1/2}$ . Let $z=(\arctan x)^{1/2}$ and take $u=\arctan x$ , so that by the chain rule

$\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}$

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}$

$\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}$

So we have

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}$

You can rewrite this a bit by factoring $(\arctan x)^{-1/2}$ , just to make it look neater:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)$

3 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

zhannawk [14.2K]

Answer:

y=27;y=−42

Step-by-step explanation:

33−y=6;63+y=21

y=27;y=−42

I hope this helps!

3 0

3 years ago

Read 2 more answers

Need help finding the area of the shaded region

abruzzese [7]

Check the picture below, the assumption being that the 6ft line is perpendicular to the 18ft line and thus making a right-triangle.

now, if we just get the whole area of the containing parallelogram and then <u>get the area of the triangle and subtract it from that of the parallelogram's,</u> what's leftover is the area we didn't subtract, the shadead area.

$\stackrel{ \textit{\LARGE Areas}}{\stackrel{parallelogram}{(18)(10)}~~ - ~~\stackrel{triangle}{\cfrac{1}{2}(18)(6)}}\implies 180~~ - ~~54\implies 126$

7 0

3 years ago

A lies on a bearing of 040° from B.<br>Calculate the bearing of B from A.

Nimfa-mama [501]

Answer:

220°

Step-by-step explanation:

The bearing of B from A is

180° + 40° = 220°

4 0

3 years ago