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I am Lyosha [343]

3 years ago

8

Tirzah wants to put a fence around her garden. She has 22 yards of fence material. Does she have enough to go all the way around

the garden?

1 answer:

In-s [12.5K]3 years ago

7 0

<span>22 5/6. No 22 is less than 22 5/6.</span>

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A 15 m pole is leaning against a wall. The foot of the pole is 10 m from the wall. Find the angle the pole makes with the ground

nataly862011 [7]

Answer:

∅ ≈ 48.2º

Step-by-step explanation:

cos∅ = adj/hyp = 10/15 = 2/3

Therefor

∅ = arccos 2/3

use calculator

∅ = 48.189685104221402

∅ ≈ 48.2º

5 0

3 years ago

Linear, Quadratic, or Exponential?<br><br> - Linear<br> - Quadratic<br> - Exponential

Yuri [45]

Answer: This is a linear

Step-by-step explanation:

If you graph these out as coordinates on desmos as (0,2) (1,5) (2,10) (3,17) the points form a straight line which is linear as shown.

5 0

2 years ago

Tammy and Wyatt are sales associates at the same used car dealership. Their supervisor is planning to promote the employee with

lisov135 [29]

I think the answer is D. The other answers are unreasonable. Wyatt would not get the promotion and just because Tammy's lowest value is bigger than Wyatt's doesn't mean that Tammy gets the promotion. The only reasonable answer is D.

7 0

3 years ago

What is the perimeter of a rectangle that is 5.73 feet long and 0.6 feet wide?

sergij07 [2.7K]

Answer:

3.438

Step-by-step explanation:

5.73 × 0.6 = 3.438

3 0

3 years ago

Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.

natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is $y=x-x^2-2$ and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

$y'=1-2x$

It can be written as

$\frac{dy}{dx}=1-2x$

Use variable separable method to solve this differential equation.

$dy=(1-2x)dx$

Integrate both the sides.

$\int dy=\int (1-2x)dx$

$y=x-2(\frac{x^2}{2})+C$ $[\because \int x^n=\frac{x^{n+1}}{n+1}]$

$y=x-x^2+C$ ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

$-2=1-(1)^2+C$

$-2=1-1+C$

$-2=C$

The value of C is -2. Substitute C=-2 in equation (1).

$y=x-x^2-2$

Therefore the solution of the given initial value problems in explicit form is $y=x-x^2-2$ .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0

3 years ago