The answer is 141.35 ft²
Before the first break, it was painted:
150 ft² ÷ 2 = 75 ft²
Now it's left:
150 ft² - 75 ft² = 75 <span>ft²
Before the second break, it was painted:
75 </span>ft² ÷ 2 = 37.5 <span>ft²
Now it's left:
75 </span>ft² - 37.5 ft² = 37.5 <span>ft²
Before the third break, it was painted:
37.5 </span>ft² ÷ 2 = 18.75 <span>ft²
</span><span>Now it's left:
</span>37.5 ft² - 18.75 ft² = 18.75 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>18.75 ft² ÷ 2 = 9.375 <span>ft²
</span><span>Now it's left:
</span>18.75 ft² - 9.375 ft² = 9.375 <span>ft²
</span>
<span>Before the fourth break, it was painted:
</span>9.375 ft² ÷ 2 = 4.6875 <span>ft²
</span><span>Now it's left:
</span>9.375 ft² - 4.6875 ft² = 4.6875 ft²
Now, we will sum what he painted for now:
75 ft² + 37.5 ft² + 18.75 ft² + 9.375 ft² 4.6875 ft² = 141.3125 ft² ≈ 141.35 ft²
When the painter takes his fifth break, there will be <span>141.35 ft² of the wall painted.</span>
Rules in exponents:
<u>Let's review few rules before solving.</u>
- x⁰ = 1 (x can be any number)
- x⁻ⁿ (n ≠ 0 or any number below 0) = 1/xⁿ
Solution (9):
Solution (11):
- (-5)⁻²
- => 1/(-5)²
- => 1/-5 x -5
- => 1/25
Solution (15):
Solution (17):
Solution (26):
- k⁻⁴j⁰
- => k⁻⁴ x j⁰
- => k⁻⁴ x 1
- => k⁻⁴ = 1/k⁴
Solution (36):
- 7s⁰t⁻⁵/2⁻¹m²
- => 7 x s⁰ x t⁻⁵/2⁻¹ x m²
- => 7 x 1 x t⁻⁵ x 2/m²
- => 14 x t⁻⁵/m²
- => 14t⁻⁵m⁻²
Hoped this helped!
Y=3(x+1)(x-5)
I'm going to ignore 3 for now, but will add it later.
FOIL the (x+1)(x-5)
F = multiply the First numbers x and x
O = multiply the Outside numbers x and -5
I = multiply the Inside number 1 and x
L = multiply the Last numbers 1 and -5
3(x^2 + -5x + 1x + -5)
add -5x and x
3(x^2 + -4x + -5)
multiply the numbers inside the parenthesis by 3
3x^2 + -12x + -15
