2 years ago

M=0 passing through p(-2,-2)

Mathematics

1 answer:

valentinak56 [21]2 years ago

3 0

Answer:

The equation of line is y+2=0

Step-by-step explanation:

The equation of line passing through the point $(x_{1},y_{1} )$ and having slope m is

$y-y_{1} = m (x-x_{1}$

Given slope m=0 and given point is is (-2,-2)

$y-(-2)=0(x-(-2))$

$y+2=0$

therefore equation of the straight line is $y+2=0$

Therefore the straight is parallel to negative x-axis(y=-2)

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