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3 years ago

M=0 passing through p(-2,-2)

Mathematics

1 answer:

valentinak56 [21]3 years ago

3 0

Answer:

The equation of line is y+2=0

Step-by-step explanation:

The equation of line passing through the point $(x_{1},y_{1} )$ and having slope m is

$y-y_{1} = m (x-x_{1}$

Given slope m=0 and given point is is (-2,-2)

$y-(-2)=0(x-(-2))$

$y+2=0$

therefore equation of the straight line is $y+2=0$

Therefore the straight is parallel to negative x-axis(y=-2)

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Read 2 more answers

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Answer:

$\frac{7}{\sqrt{3}}$

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

$d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |$ --------------------(i)

From the question,

the point is (5, 0, -6)

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Therefore,

a = 5

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c = -6

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Substitute these values into equation (i) as follows;

$d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |$

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$d = |\frac{(-7)}{\sqrt{3}} |$

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