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il63 [147K]
2 years ago
14

Look at this angle TUV what are the sides

Mathematics
1 answer:
enot [183]2 years ago
8 0

Answer:

Socratic app

Step-by-step explanation:

it will help you

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Find the sum (a-b)(2a+4b)
Mama L [17]
(a-b)(2a+4b) = 2a² - 2ab + 4ab - 4b² =  2a² + 2ab - 4b²
7 0
3 years ago
Of 6.5 hectoliters of fuel, the private spilled 350 milliliters. how many liters did the private spill?
sergiy2304 [10]

The private spilled 0.35 litres of fuel

<h3>How to calculate the amount of litres spilled ? </h3>

The first step is to convert 6.5 hectolitres to litres

= 6.5 × 100

= 650 litres

Next is to convert millilitres to litres

= 350/1000

= 0.35 litres

Hence the number of litres spilled is 0.35 litres

Read more here

brainly.com/question/18239674?referrer=searchResults

#SPJ1

7 0
2 years ago
Solve the following equation for x: 6(4x + 5) = 3(x + 8) + 3. Round to the nearest hundredth.
Vera_Pavlovna [14]

Answer:

\boxed {x = -\frac{1}{7}}

Step-by-step explanation:

Solve for the value of x:

6(4x + 5) = 3(x + 8) + 3

-Use <u>Distributive Property</u>:

6(4x + 5) = 3(x + 8) + 3

24x + 30 = 3x + 24 + 3

-Combine like terms:

24x + 30 = 3x + 24 + 3

24x + 30 = 3x + 27

-Take 3x and subtract it from 24x:

24x + 30 -3x = 3x - 3x + 27

21x + 30 = 27

-Subtract both sides by 30:

21x + 30 - 30 = 27 - 30

21x = -3

-Divide both sides by 21:

\frac{21x}{21} = \frac{-3}{21}

x = \frac{-3}{21}

-Reduce the fraction to the lowest term by extracting and canceling out 3:

x = \frac{-3\div3}{21 \div 3}

\boxed {x = -\frac{1}{7}}

Therefore, the value of x is -\frac{1}{7}.

5 0
3 years ago
Give an example of each of the following or explain why no such example exists. (a) Two polynomials of degree 1 in Z4x whose pro
andre [41]

Answer:

Step-by-step explanation:

(a)

let, f(x) = 2x+1 & g(x) = 2x+2

So, f(x).g(x) = (2x+1).(2x+2) = 4x² + 6x + 2 = 2x+2 in Z_4[x]

So, product of two 1 degree polynomials is a 1-degree polynomial in Z_4[x]

(b)

let, f(x) = 2x³ - 3x² + 5x + 7 & g(x) = -2x³ + 3x² + x + 3 be two polynomials in R[x]

So, f(x) + g(x) = 6x + 10, which is a polynomial of degree 1 in R[x]

(c)

this is not possible, since, if f & g are 2 polynomials in any polynomial ring S, then, we always have,

deg(f.g) <= deg(f) + deg(g)

So, deg(f.g) = 5 (as desired) but, deg(f) + deg(g) = 2+2 = 4 but, 4 < 5

So, this is not possible.

So, no such example exists.

3 0
3 years ago
Help pleasee i need it done ASAP
Scrat [10]

Answer:

8

6

4

2

0

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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