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3 years ago

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Find the equation of a line passing through the point (6,−5) and parallel to the line y = 7x + 1. answers : y = 7x − 47 y = −17x

+ 41 y = −17x +477 y = 7x − 29

1 answer:

Elan Coil [88]3 years ago

3 0

Answer:

<h2>y = 7x-47</h2>

Step-by-step explanation:

$y = 7x + 1.\\(6,-5)\\m= 7\\x1= 6\\y1 = -5\\y-y1=m(x-x1)\\y-(-5) = 7(x-6)\\y+5=7x-42\\y=7x-42-5\\y = 7x-47$

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If a and b are the roots of 11x^2-4x-2=0 then compute the product: (1+a+a^2+...)(1+b+b^2+...)

lisov135 [29]

Answer:

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Step-by-step explanation:

FirLet a and b be the roots of 11x^2-4x-2=0

Now $(1+a+a^2+\cdots)(1+b+b^2+\dcots)=\frac{1}{1-a}\cdot \frac{1}{1-b}\\=\frac{1}{(1-a)(1-b)}=\frac{1}{1-(a+b)+ab}$

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3 years ago

Circle A has a Circumference of approximately 314.159 feet. Circle B has a diameter that is half the size of Circle A. Which is

Kaylis [27]

The diameter of circle B is 50 cm.

Step-by-step explanation:

Given,

The circumference of circle A = 314.159 ft

Diameter of Circle B is half of the diameter of circle A.

Let, the radius of circle A is r

To find the diameter of circle B

Formula

Circumference of a circle of radius r = 2πr

According to the problem,

2πr = 314.159

or, r = $\frac{314.159}{2X3.14}$

= 50 (approx)

So,

The diameter of circle A = 2×50 cm = 100 cm

The diameter of circle B = 50 cm.

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