What operation do you need to use when you factor out the greatest common factor in an expression? *
2 answers:
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Answer:
See explanation
Step-by-step explanation:
Solution:-
- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:
P ( x ) = 50 Ln ( 50 / x ).
- The point price elasticity ( E ) of demand is given by:
- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.
- To determine the " dP / dx " by taking the first derivative of the given relation:
P ( x ) = 50 Ln ( 50 / x ).
d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]
= - 50 / x
- Hence the point price elasticity of demand is given by:
E = - ( P / x ) * ( 50 / x )
E = -50*P / x^2
- For an inelastic demand, ! E ! is < 1:
! -50*P / x^2 ! < 1
50*P / x^2 < 1
P < x^2 / 50
- For an unitary demand, ! E ! is = 1:
! -50*P / x^2 ! = 1
50*P / x^2 = 1
P = x^2 / 50
- For an inelastic demand, ! E ! is > 1:
! -50*P / x^2 ! > 1
50*P / x^2 > 1
P > x^2 / 50
2)
If the unit price is increased slightly from $50, will the revenue increase or decrease?
- We see from the calculated demand sensitivity d P / dt:
d P ( x ) / dx = - 50 / x
- We see that as P increases the from P = $50, the quantity of goods demanded would be:
50 = 50 ln(50/x)
1 = Ln ( 50 / x )
50/x = e
x = 50 / e
Then,
d P ( x ) / dx = - 50 / ( 50 / e )
d P ( x ) / dx = - e
- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.
- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:
Revenue R ( x ) = P ( x ) * x
= 50*x*ln(50/x)
Then the product of price and quantity goods also decreases; hence, revenue decreases.
Answer:
15, 8, 66%, 40
Step-by-step explanation:
Hi! ok so in ogive charts its really about finding the corresponding data points and sometimes it's a lot of estimation so these answers may not be exact but they'll be close.
In the image, you'll see a bunch of lines, basically what youre doing is finding the corresponding frequency of the dollars or vice versa.
<em>question a)</em>
50 dollars or less, so the area of 50 dollars and below that.
from the chart we can see that this lines up to around 15 people.
<em>question b)</em>
now this one is a little bit more challenging, but you can use the same process as you did for the first question. so we can see who spent 100 dollars or less. this value is around 42 (just from looking at the graph)
<em>we know if you didn't spend 100 dollars or less, you must have spent more than that. </em>
so take 50-42=8
around 8<u> people</u> spent 100 dollars or more.
<em>question c)</em>
basically the same question as the first but more calculations are involved. from the graph we can see around 33 people spent 80 dollars or less. but the question is asking the percentage. so what percent of 50 (people) is 33.
33/50 = 0.66
around 66%
<em>question d)</em>
80th percentile means less than or equal to 80% of the frequencies/the data. so we first need to find what value that is in terms of frequency.
50 times 0.8 = 40
40 people
now just plot that on the graph (sorry i did it wrong in the image)
