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xxMikexx [17]
3 years ago
7

A car and a scooter are moving in opposite directions and cross each other at a common point. if the average speed of the car is

50 miles per hour and that of the scooter is 40 miles per hour,after how many hours will they be 180 miles apart?
Mathematics
1 answer:
Tema [17]3 years ago
6 0
As they are traveling in opposite directions you need to do 50 + 40 to find out how far apart they travel every hour. 50 + 40 = 90. So you know that they are 90 miles apart every hour.
180 / 90 = 2. so you know that it takes them 2 hours to be 180 miles apart.
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Answer:

<u>4(1 – x) + 2 x = -3( x + 1)</u>

first do 4 time 1= 4

then do 4 times x =4x

now the equation should look like this

4-4x+2x=-3(x+1)

then do the other side of the equation

-3(x+1)

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Now collect the like terms:

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now the equation should look like this

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4-2x+3x=-3

put the 4 on the other side

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now again collect the like terms (-2x+3x=1 which is just x and -3-4 =-7)

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a famer has 120 feet of fencing with whcih to enclose two adjacent rectangular pens as shown. what dimeensions should be used th
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The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.

Let the area be y .

Area = (base) × (height)

Base = 2x

Height = h

Let the area of the rectangular pens be y .

∴ y = 2xh

Perimeter of all the fencing = 4x+3h

∴ 4x+3h = 120

now we solve for h

3h = 120-4x

h = 40 - 4/3 x

Now we will substitute this value in the above first equation:

y = 2xh

or, y = 2x (40 - 4/3 x)

or, y = 80x - 8/3 x²

Now for the maximum area we have to find the first order differentiation of y

now,

dy /dx = 80 - 16/3 x

At dy/dx = 0 we get the value of x for which y is maximum.

80 - 16/3 x = 0

or, - 16/3 x = -80

or, x = 15 feet

Hence height =  40 - 4/3 x = 40 - 20 = 20feet

Maximum area = 2xh = 2×15×40 = 1200 square feet

The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.

Disclaimer : The missing figure for the question is attached below.

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