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Sedaia [141]
2 years ago
9

What is three fifths times 2 and five sixths

Mathematics
1 answer:
MrRissso [65]2 years ago
8 0
Three fifths times 2 and five sixths is 1.7
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64 decreased by twice vanessas height as an algebraic expression
Dima020 [189]

Let vanessa's height = v.

twice of vanessa's height = 2v

64 decreased by... = 64 -

64 - 2v is your algebraic expression

hope this helps

3 0
3 years ago
The sum of the digits of a two-digit number is 5. If nine is subtracted from the number, the digits will be reversed. Find the n
Komok [63]
The number is 32
X-9=23
5 0
2 years ago
Lara read for 40 minutes. She read 4 times longer than Ryan. Which equation could be used to calculate the number of minutes tha
Maru [420]
The answer is A. because if she read 4 times as much, p multiplied by 4= 40
7 0
2 years ago
Jane needs to buy mulch to cover a circular garden
scoray [572]

Answer:

$3089.4

Step-by-step explanation:

A circle is a locus of a point such that its distance from a point known as the center is always constant.

The area of a circle is given by the formula:

Area = πr²; where r is the radius of the circle.

From the image attached, we can see that the garden is circular with a radius of 5.5 yard. Hence:

Amount of mulch needed to cover garden = area of garden = πr² = π(5.5)²  = 95 yd²

Since mulch cost $32.52 per square yard, hence:

Cost of mulch needed = $32.52 per yd² * 95 yd² = $3089.4

7 0
2 years ago
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
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