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stiv31 [10]
3 years ago
10

Help........plsplav j h

Mathematics
1 answer:
KatRina [158]3 years ago
5 0
Just did this one! The answer is 41/200 :)
Explication: 2*1/10=0.2
5*1/1000=0.005
0.2+0.005=2.05 (I think)
So the answer is 41/200! (Btw I was confirmed correct!) :)
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Which of the four triangles efG
Marat540 [252]
Sorry in order to answer this I need the picture of the 4 triangles
7 0
3 years ago
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On a certain hot summer day, 481 people used the public swimming pool. The daily prices are 1.25 for children and 2.25 for adult
spayn [35]

Answer:the number of children that swam in the public pool that day is 222

the number of adult that swam in the public pool that day is 259

Step-by-step explanation:

Let x represent the number of children that swam in the public pool that day.

Let y represent the number of adult that swam in the public pool that day.

On a certain hot summer day, 481 people used the public swimming pool. This means that

x + y = 481

The daily prices are 1.25 for children and 2.25 for adults. The receipts for admission totaled to 86.25. This means that

1.25x + 2.25y = 860.25 - - - - - - - -1

Substituting x = 481 - y into equation 1, it becomes

1.25(481 - y) + 2.25y = 860.25

601.25 - 1.25y + 2.25y = 860.25

- 1.25y + 2.25y = 860.25 - 601.25

y = 259

Substituting y = 259 into x = 481 - y, it becomes

x = 481 - 259

x = 222

8 0
3 years ago
Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0​
katrin [286]

Answer:

a= 1 , b= 3 , c= –3

x =  \frac{ - b \frac{ + }{}  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 3  \frac{ + }{} {}  \sqrt{ {3}^{2}  - 4(1)( - 3)} }{2(1)}  \\  =   \frac{ - 3 \frac{ + }{}  \sqrt{9 + 12} }{2}  =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\ \\  x =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\  \\ x = 0.79 \\ x =  - 3.79

I hope I helped you^_^

4 0
3 years ago
Which is the best approximation of the solutions to the system of equations graphed below?
Neko [114]

According to the direct inspection, we conclude that the best approximation of the two solutions to the system of <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>

Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the <em>Cartesian</em> plane.

According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

To learn more on quadratic equations: brainly.com/question/17177510

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4 0
2 years ago
If r(x)=2-x^2 and w(x)=x-2, what is the range of (w*r)(x)
horrorfan [7]
First, find the product (w*r)(x):  (w*r)(x) = (x-2)*[2-x^2] = 2x - x^3 - 4 + 2x^2

This is a cubing function.  Since the sign of the cube-of-x term is negative, the graph will begin in Quadrant II and pass through Quadrant IV.  There are no limits on y.  Thus, the range is (-infinity, +infinity).

5 0
3 years ago
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