Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
Answer:
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Step-by-step explanation:jjjj
Answer
MULTIPLY 2.2 & 5.5
Step-by-step explanation:
Step-by-step explanation:
formula is
v = 4/3 * pi * r^3
r = 8.8
answer is 2854.54
Answer:
Paula get and Kawai get .
Step-by-step explanation:
Given: Paula and Kawai shared in the ratio of .
To find: How much money did each person get?
Solution:
We have,
Paula and Kawai shared in the ratio of .
So, let Paula get and Kawai get .
As per the question,
Therefore, Paula get , and Kawai get .
Hence, Paula get and Kawai get .