The previous population was 14000.
Explanation
The population decreased by 35% since the last measurement. So the current population is less than the previous population.
current population=9100
previous population =x
current population is 35% less than the previous population x
The previous population was 14000.
Answer: b
Step-by-step explanation: since i helped can i have brainlist please :D
The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)
<h3>How to determine the total areas?</h3>
<u>The figure 1</u>
In this figure, we have
Length = x + 1
Width = 4
The area is calculated as:
Area = Length * Width
So, we have
Area = 4(x + 1)
<u>The figure 2</u>
In this figure, we have
Length = d + 4
Width = 7
The area is calculated as:
Area = Length * Width
So, we have
Area = 7(d + 4)
<u>The figure 3</u>
In this figure, we have
Length = y + 3
Width = y
The area is calculated as:
Area = Length * Width
So, we have
Area = y(y + 3)
Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)
Read more about areas at:
brainly.com/question/24487155
#SPJ1
Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
