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3 years ago

What would be the solution to the inequality? x-20<100

Mathematics

2 answers:

scoray [572]3 years ago

8 0

I believe the answer is x<120

BlackZzzverrR [31]3 years ago

4 0

Answer:

the answer would be anything between 0-119 because any of these numbers minus 20 is still less than 100

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Evan earns $21.50 per hour for 25 hours and time and a half for overtime. If he worked 5 hours

Andrei [34K]

21.50 x 25 = 537.50
10.75 x 5 = 53.75

537.50 + 53.75 = 591.25

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2 years ago

550 is 5% of what number? Which statements are correct? Check all that apply. The answer will be smaller than 550. The answer wi

OLga [1]

Answer:

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Step-by-step explanation:

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A company has two large computers. The slower computer can send all the company's email in 60 minutes. The faster computer can c

Lelu [443]

Answer:

If both computers are working together, it will take 24 minutes to do the job

Step-by-step explanation:

It is given that,

There are two computers.The slower computer can send all the company's email in 60 minutes.

The faster computer can complete the same job in 40 minutes

To find the LCM of 40 and 60

LCM (40, 60) = 120

To find efficiency of 2 computers

Let x be the efficiency of faster computer and y be the efficiency of faster computer

x = 120/40 = 3

y = 120/60 = 2

then, x + y = 3 + 2 = 5

Therefore efficiency of both the computer work together = x + y =5

To find the time taken to work both the computer together

time = 120/5 = 24 minutes

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3 years ago

In a chess club the probability that Shaun will beat Mike is 3/8 .

romanna [79]

Answer:

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

Step-by-step explanation:

Games are independent, so we find each separate probability, and multiply them.

In a chess club the probability that Shaun will beat Mike is 3/8.

So $1 - \frac{3}{8} = \frac{8}{8} - \frac{3}{8} = \frac{5}{8}$ probability that Shaun loses.

The probability that Shaun will beat Tim is 5/7 .

So $1 - \frac{5}{7} = \frac{2}{7}$ probability that Shaun loses.

What is the probability that Shaun loses both games?

This is:

$p = \frac{5}{8} \times \frac{2}{7} = \frac{5*2}{8*7} = \frac{10}{56} = 0.1786$

$\frac{10}{56} = 0.1786$ probability that Shaun loses both games

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3 years ago

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krok68 [10]

The range is 10 to 40 and then the rest .
Hoped I helped by have a create day!okemzkzkkdkxdkjxkfjjzkekkdkekzkdkdkdkdiididididiididiididodododo

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3 years ago

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