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3 years ago

Which of the following ratios would form a proportion with 4/5?

Mathematics

2 answers:

BabaBlast [244]3 years ago

4 0

Answer:

Can you explain clearer?

Step-by-step explanation:

leonid [27]3 years ago

4 0

Where are the following ratios
umm can I get brainliest please

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What is the measurement of a square

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A square is made up of 4 equal length lines connected at 90 degree angles so. the total angle measurement of all 4 inside corners of a square of any size is 360 degrees.

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How do you solve this?

max2010maxim [7]

Would 104/2 work? You get 52 which is the same as 24+28.

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3 years ago

When using statistics in a speech, you should usually Group of answer choices manipulate the statistics to make your point. cite

NARA [144]

Answer:

Avoid Using too many statistics

Step-by-step explanation:

when a speaker is giving a speech, the listeners prefer main points to hearing too much of statistics. Too many statistics bore the audience and sometimes divert their attentions from the crux of the speech. If statistics are to be given, they must be clearly expressed and the source should be clearly stated.

Numbers that are of large decimal points can be rounded off so as not to confuse the audience and to make them grasp the main idea.

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3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

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2 years ago

Nth term of 4,11,18,25

romanna [79]

18 is the answer because eighteenth has nth in the ending

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2 years ago

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