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oee [108]
1 year ago
15

Please I need help!!

Mathematics
1 answer:
telo118 [61]1 year ago
7 0

The regression equation which correctly models the data in this table is y = 1.49x - 107.5,

<h3>How to determine the regression equation?</h3>

From the table of data values, we have the following parameters:

∑x = 632

∑y = 404

∑x² = 80.142

∑xy = 51.448

Mathematically, the regression equation is represented by the following slope equation:

y = Bx + A

Next, we would determine A by using this expression:

A = (∑y·∑x² - ∑x·∑xy)/(n∑x² - (∑x)²)

A = (404×80,142 - 632×51,448)/(5×∑x² - (632)²)

A = (32,377,368 - 32,515136)/(5×80142 - 399,424)

A = -137,768/1286

A = 107.5

For B, we have:

B = (n∑xy· - ∑x·∑y)/(n∑x² - (∑x)²)

B = (5×51,448 - 632×404)/(5×∑x² - (632)²)

B = 1.49.

y = Bx + A

y = 1.49x - 107.5

Read more about regression equation here: brainly.com/question/28037520

#SPJ1

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Not the same.

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Reflection over the y axis make the coordinates (x,y) as (-x,y)

i.e. this means rotation of 180 degrees about the origin anticlockwise.

Hence just rotation of 180 degrees is not the same as a reflection over y axis.

The conditions are:

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A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban
zalisa [80]

Answer:

<u>4212 : 1573</u> is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be x.

<em>As, sign is similar to banner.</em>

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to x.

\frac{36}{52} =\frac{22}{x}

<em>By cross multiplying we get:</em>

<em />36x=1144<em />

<em>Dividing both sides by 36 we get:</em>

x=31\frac{7}{9} .

<em>Hence, the width of sign is </em>31\frac{7}{9}<em> inches.</em>

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

Area\ of\ banner=36\times 52

Area\ of\ banner=1872\ square\ inches.

Now, area of sign:

Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

1872:\frac{6292}{9}

=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}

<em>On simplifying we get:</em>

=\frac{4212}{1573}

=4212:1573.

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

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9.18 \cdot 2 = \boxed{18.36}.

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