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chubhunter [2.5K]
3 years ago
15

Help this is due in 1 hour .

Mathematics
2 answers:
kvv77 [185]3 years ago
8 0

Answer:

C

Step-by-step explanation:

it is c because the x axis is 3 and three over and the y axis it is right on 4

olga55 [171]3 years ago
4 0

Answer:

b

Step-by-step explanation:

just out b i dont have time to explain

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What is 1/4(x+16)-x equal too
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<span>1/4(x + 16) - x =

First, distribute the 1/4.

= 1/4x + 1/4 * 16 - x

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3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

y=2x

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\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

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a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

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murzikaleks [220]
4900 is the answer :)
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