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IceJOKER [234]
3 years ago
15

John is playing a gamr of darts. The probability that he throws a dart into the center of the dart board (bulls eyes) is 1/10. T

he probability tgat he throws rhe dart the dart into the dart into the 10 point ring is 3/10. What is the probability that he either hits a bullseye or scores 10 points?
Mathematics
2 answers:
dangina [55]3 years ago
5 0

Answer:

2/5

Step-by-step explanation:

Natali [406]3 years ago
5 0

Answer:

\bf\textbf{The probability that he either hits a bulls eye or scores 10 points = }\frac{2}{5}

Step-by-step explanation:

\text{The probability that he throws a dart into the center of the dart board = }\frac{1}{10}

\text{The probability that he throws the dart into the 10 point ring = }\frac{3}{10}

Now we need to find the probability that he either hits a bulls eye or scores 10 points.

The probability that he either hits a bulls eye or scores 10 points = Probability that he hits the bulls eye + Probability that he throws the dart into the 10 point ring

\text{The probability that he either hits a bulls eye or scores 10 points = }\frac{1}{10}+\frac{3}{10}

\text{The probability that he either hits a bulls eye or scores 10 points = }\frac{4}{10}

\bf\textbf{The probability that he either hits a bulls eye or scores 10 points = }\frac{2}{5}

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