Answer:
2/3
Step-by-step explanation:
<em>Answer</em>
B) y = 3
<em>Step-by-step explanation</em>
Given the system of equations:

Isolating x from equation 1:

Substituting equation 3 into equation 2 and solving for y:

The formula to calculate work done is -
Work done ( in joule, J) = Force (in Newton) X Distance (in meters)
So, we will use the formula to calculate work done,
Here, force is given as = 7 newtons
Distance is given as = 3 meters
So, work done will be -
Work done ( in joule, J) = 7 Newtons X 3 Meters
<u>Work done ( in joule, J) = 21 J (in joule)</u>
Answer:
-18w+2
Step-by-step explanation:
6*-3w=-18w
1/3*6=2
Answer:r-1
Step-by-step explanation:
(-r-5)-(-2r-4) Or (-r-5)-(-2r-4)
-r+-5+2r+4. -r-5+2r+4
r-1 r-1
You bring down the first Parentheses Then have to multiply the (implied 1) -1•-2=2 and -1•-4=4 and do the math regularly