How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?
2 answers:
This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible =
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible =
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible =
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83
You might be interested in
Answer:
Constant of proportionality k = 3.5
In our case, We can say that Amount of 1 quart is $3.5, and as the number of quarts bought are increased the amount paid is also increased at rate of $3.5.
Step-by-step explanation:
We need to find what is the constant of proportionality, and what does it mean in this situation?
Constant of proportionality can be defined as:
Where k is constant of proportionality
It tells that there is constant increase in the value of y.
Looking at the graph,
we get Number of Quarts (x) = 1, Amount Paid (y)= 3.5
so, finding constant of proportionality
Now, Number of Quarts (x) = 2, Amount Paid (y)=7
so, finding constant of proportionality
So, for any value of x and y, the value of k remains constant i.e 3.5
So, constant of proportionality k = 3.5
In our case, We can say that Amount of 1 quart is $3.5, and as the number of quarts bought are increased the amount paid is also increased at rate of $3.5.
<em>*100% CORRECT ANSWERS</em>
Hey!
Here is the equation:
Switch the equation around and i becomes:
Multiply 2.5 by 6
<em>That means your answer is 15</em>