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2 years ago

A Janine tem hoje 4 anos e daqui a 8 anos sua idade será 1 terço da idade de seu pai.

Mathematics

1 answer:

goblinko [34]2 years ago

6 0

12= 1/3*x 12= x/3 36=x Hoje ela tem 4 anos, daqui a 8 anos terá 12 anos, que é um terço da idade de seu pai, 12*3=36

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WRITE THE FOLLOWING EQUATION IN THE FORM OF Y=MZ (a) 3x+4y=7

Shalnov [3]

Answer:

$y = \frac{ - 3x}{4} + \frac{7}{4}$

Step-by-step explanation:

First transpose 3x

you are having 3x+4y=7

by transposing you will get

4y=-3x+7

divide by 4 throughout by making y subject of the formula you will find your equation as y=mx+c.

4 0

2 years ago

keri rented a canoe from a rental company for atotal of $35.00 the company charges $10.50 for the first hour and $8.25 per hour

Zielflug [23.3K]

Answer:

She rented it for 3 hours.

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1 year ago

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TEA [102]

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3 years ago

Whats the answer to 8.4 + 0.18x = 0.32x

Sveta_85 [38]

Step-by-step explanation:

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3 0

2 years ago

A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro

Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let $\mu$ be the true mean weight per apple the company ship. We want to test the next hypothesis

$H_{0}:\mu=120$ vs $H_{1}:\mu\neq 120$ (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

$Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}}$ which is normally distributed. The observed value is

$z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583$ . The rejection region for $\alpha = 0.05$ is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0

3 years ago