I need help with this question please
1 answer:
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I may be incorrect so verify with someone
(2×3-18x+5) ÷(x-3)
(6-18x +5) ÷ (x-3)
11-18x ÷x-3
the last part is in the image
GOOD LUCK
PLEASE GIVE ME BRAINLIEST BECAUSE THIS WAS KINDA HARD
(2×3-18x+5) ÷(x-3)
(6-18x +5) ÷ (x-3)
11-18x ÷x-3
the last part is in the image
GOOD LUCK
PLEASE GIVE ME BRAINLIEST BECAUSE THIS WAS KINDA HARD
Answer:
she turned 82 degrees.
Step-by-step explanation:
Suppose, the unknown angle is A
Now, we know that according to the sine law ,
the ratio of side of a triangle and the sine value of the angle opposite to that side is same . It says that,
if a triangle has 3 sides a,b and c and 3 angles A,B,and C and they are opposite to the sides respectively then,
a/SinA=b/sinB=c/SinC
check the image below in attachment.
From the diagram at attachment.
here , angle A is required.
given, angle C= 30
side b=89 m and c= 48 m
sin law says a/sinA=b/sinB=c/sinC
first we take , b/sinB=c/sinC
or, 89/sinB= 48/sin30
or, sinB=( 89×0.5)/48 =0.92
or, B=68
we know, in every triangle , the sum of 3 angles of a triangle is 180
then, A+B+C=180
or, A=180-B-C= 180 - ( B+C)
=180-(68+30)
or, A = 82
therefore , the required angle is 82 degree.
she turned 82 degrees.
