Answer:
112
Step-by-step explanation:
Answer:
a = 13.8
(missing length of triangle = 13.8 meters)
Step-by-step explanation:
The side lengths of a triangle can be related using the Pythagorean Theorem;
a² + b² = c²
where
a = one side length
b = other side length
c = hypotenuse (long side --across from 90° angle)
So, by plugging our values into the Pythagorean Theorem, we can solve for a:
a = unknown
b = 18.4
c = 23
a² + b² = c²
a² + 18.4² = 23²
a² + 338.56 = 539
- 338.56 - 338.56 {subtract 338.56 from both sides to isolate a}
a² = 190.44
√a² = √190.44
a = 13.8
so, the missing length of the triangle is 13.8 m
hope this helps!!
Answer:
a. 1620-x^2
b. x=810
c. Maximum value revenue=$656,100
Step-by-step explanation:
(a) Total revenue from sale of x thousand candy bars
P(x)=162 - x/10
Price of a candy bar=p(x)/100 in dollars
1000 candy bars will be sold for
=1000×p(x)/100
=10*p(x)
x thousand candy bars will be
Revenue=price × quantity
=10p(x)*x
=10(162-x/10) * x
=10( 1620-x/10) * x
=1620-x * x
=1620x-x^2
R(x)=1620x-x^2
(b) Value of x that leads to maximum revenue
R(x)=1620x-x^2
R'(x)=1620-2x
If R'(x)=0
Then,
1620-2x=0
1620=2x
Divide both sides by 2
810=x
x=810
(C) find the maximum revenue
R(x)=1620x-x^2
R(810)=1620x-x^2
=1620(810)-810^2
=1,312,200-656,100
=$656,100
Answer: The measures of all the three angles are 24 , 60 and 96
Step-by-step explanation:
Since the measures are given in ratio form, the first thing is to find the total ratio, which is
2 + 5+ 8 = 15
Recall that the sum of angles in a triangle is 180 ,so to calculate each angle , we have
2/15 x 180 = 24
also , 5/ 15 x 180 = 60
Finally, 8/15 x 180 = 96
The triangle is obtuse , since it is having one angle greater than 90.
It can not be acute because of the existence of 96 , for a triangle to be acute , all the angles must be less than 90 , and it can not be right triangle because there is no existence of 90
Until the concerns I raised in the comments are resolved, you can still set up the differential equation that gives the amount of salt within the tank over time. Call it

.
Then the ODE representing the change in the amount of salt over time is



and this with the initial condition

You have


![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/250}A(t)\right]=\dfrac25e^{t/250}(1+\cos t)](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F250%7DA%28t%29%5Cright%5D%3D%5Cdfrac25e%5E%7Bt%2F250%7D%281%2B%5Ccos%20t%29)
Integrating both sides gives


Since

, you get

so the amount of salt at any given time in the tank is

The tank will never overflow, since the same amount of solution flows into the tank as it does out of the tank, so with the given conditions it's not possible to answer the question.
However, you can make some observations about end behavior. As

, the exponential term vanishes and the amount of salt in the tank will oscillate between a maximum of about 100.4 lbs and a minimum of 99.6 lbs.