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PtichkaEL [24]
3 years ago
12

Jason is traveling by car from his home to his office. He has gone 3.5 miles so far. From this point on, he can cover 100 miles

every 2 hours. What is the equation of a line that models the total miles traveled, y, in x hours after this point?
Mathematics
1 answer:
Elden [556K]3 years ago
7 0
First the equation needs to be set to "y" to find the total amount of miles traveled:
y=
Then you know he has already gone 3.5, this is a constant and can be added to the graph immediately
y=3.5
Then you know every two hours he can cover 100 miles, which means 50 miles per hour or 50 per x, so add 50x to 3.5 to show that he will go 3.5 miles plus 50 miles for every hour he is traveling.
y=3.5+50x
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Find the value of x. If necessary, you may learn with the markings on a figure indicate.
love history [14]

Answer:

112

Step-by-step explanation:

6 0
3 years ago
Find the missing length of the triangle.
jek_recluse [69]

Answer:

a = 13.8

(missing length of triangle = 13.8 meters)

Step-by-step explanation:

The side lengths of a triangle can be related using the Pythagorean Theorem;

a² + b² = c²

where

a = one side length

b = other side length

c = hypotenuse (long side --across from 90° angle)

So, by plugging our values into the Pythagorean Theorem, we can solve for a:

a = unknown

b = 18.4

c = 23

a² + b² = c²

a² + 18.4² = 23²

a² + 338.56 = 539

    - 338.56   - 338.56       {subtract 338.56 from both sides to isolate a}

a² = 190.44

√a² = √190.44

a = 13.8

so, the missing length of the triangle is 13.8 m

hope this helps!!

6 0
2 years ago
Read 2 more answers
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
4 years ago
The measures of the angles of a triangle are in the ratio of 2 : 5 : 8
andrezito [222]

Answer: The measures of all the three angles are 24 , 60 and 96

Step-by-step explanation:

\\Since the measures are given in ratio form, the first thing is to find the total ratio, which is

\\2 + 5+ 8 = 15

\\Recall that the sum of angles in a triangle is 180 ,so to calculate each angle , we have

\\2/15 x 180 = 24

\\also , 5/ 15 x 180 = 60

\\Finally, 8/15 x 180 = 96

\\The triangle is obtuse , since it is having one angle greater than 90.

\\It can not be acute because of the existence of 96 , for a triangle to be acute , all the angles must be less than 90 , and it can not be right triangle because there is no existence of 90

7 0
3 years ago
A 500 gallon tank initially contains 200 gallons of water with 5 lbs of salt dissolved in it. Water enters the tank at a rate of
Lapatulllka [165]
Until the concerns I raised in the comments are resolved, you can still set up the differential equation that gives the amount of salt within the tank over time. Call it A(t).

Then the ODE representing the change in the amount of salt over time is

\dfrac{\mathrm dA}{\mathrm dt}=\text{rate in}-\text{rate out}
\dfrac{\mathrm dA}{\mathrm dt}=\dfrac{2\text{ gal}}{1\text{ hr}}\times\dfrac{\frac15(1+\cos t)\text{ lbs}}{1\text{ gal}}-\dfrac{2\text{ gal}}{1\text{ hr}}\times\dfrac{A(t)\text{ lbs}}{500+(2-2)t}
\dfrac{\mathrm dA}{\mathrm dt}=\dfrac25(1+\cos t)-\dfrac1{250}A(t)

and this with the initial condition A(0)=5

You have

\dfrac{\mathrm dA}{\mathrm dt}+\dfrac1{250}A(t)=\dfrac25(1+\cos t)
e^{t/250}\dfrac{\mathrm dA}{\mathrm dt}+\dfrac1{250}e^{t/250}A(t)=\dfrac25e^{t/250}(1+\cos t)
\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/250}A(t)\right]=\dfrac25e^{t/250}(1+\cos t)

Integrating both sides gives

e^{t/250}A(t)=100e^{t/250}\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)+C
A(t)=100\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)+Ce^{-t/250}

Since A(0)=5, you get

5=100\left(1+\dfrac1{62501}\right)+C\implies C=-\dfrac{5937695}{62501}

so the amount of salt at any given time in the tank is

A(t)=100\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)-\dfrac{5937695}{62501}e^{-t/250}

The tank will never overflow, since the same amount of solution flows into the tank as it does out of the tank, so with the given conditions it's not possible to answer the question.

However, you can make some observations about end behavior. As t\to\infty, the exponential term vanishes and the amount of salt in the tank will oscillate between a maximum of about 100.4 lbs and a minimum of 99.6 lbs.
5 0
4 years ago
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