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tigry1 [53]
3 years ago
9

Find three different irrational numbers between the rational numbers 0.13 and 0.14

Mathematics
2 answers:
drek231 [11]3 years ago
4 0
In order to solve this problem easily you coin this method: Find the squares of 0.13 and 0.14. They are respectively 0.0169 and 0.0196. Irrational numbers are going to located between this interval, considering that we are not counting perfect squares. \sqrt{0.0168} ,  \sqrt{0.017} , \sqrt{0.0175} are the three possible answers. 
Sergeeva-Olga [200]3 years ago
3 0

Answer:

They can be :

0.131131113111131111....

0.132132213222132222....

0.133133313333133333...

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garri49 [273]
This one is D
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3 0
3 years ago
PLEASE HELP!! (click on the pic)
Vesna [10]

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5 0
3 years ago
Read 2 more answers
8(3x + 9)-2<br><br><br> A.24x+56 <br><br> B.24x+7 <br><br> C.24x+70 <br><br> D.24x+72
FromTheMoon [43]

Step-by-step explanation:

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C.24x+70.........

3 0
3 years ago
Read 2 more answers
1. Which expresses the given inequality in interval notation?
Digiron [165]
1)  x < 4  the answer is  <span>  Option C: x E(-infinity,4)  (it is strict)
2)  </span>2x +6 < 8, and  <span>2x < 8 - 6 = 2, and x<2/2=1
the answer is </span>
<span>D. x E (-infinity, 1)
</span>3)  <span>X greater than or equal to 8 and  x <  - 4
</span>X greater than  8  means x ≥ 8
so we have x ≥ 8 and  <span> x <  - 4
so the answer is  </span>
<span>B. x E (-4,8]
</span> 4) 
7 > x + 6 or x -2 greater than or equal to 3,
<span>7 > x + 6 or x -2 ≥ 3
</span>
<span>7 -6> x, and 1>x
</span>
x -2 ≥ 3   x<span>≥ 3+2=5
finally
</span>x<1 and x≥5   

the answer is
<span>C.x E (1,5]
5)
</span>
|x+3| > 12, 
|x+3| = { -(x+3) if <span>x+3<0 or  </span><span>(x+3)  if </span><span>x+3>0}</span>

so, it is  -(x+3)>12 is equivalent to (x+3)< -12  or (x+3)>12
the answer is
<span>B. x + 3 > 12 or x + 3 <-12</span>






7 0
3 years ago
Read 2 more answers
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